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raketka [301]
3 years ago
5

If a coin has a mass of 29.34g and drops from a height of 14.7 meters, what is its loss in gravitational potential energy? Show

work.
Physics
1 answer:
Serga [27]3 years ago
7 0
U= mgh
U=((29.34/1000)kg)(9.81 \frac{m}{s^{2} } )(14.7m)=4.321J

do not forget to change grams to kilograms and if it were in centimeters convert them to meters.
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Electromagnetic waves with low frequencies have been used for long-distance underwater communication. These waves most likely be
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These waves most likely belong to the part<span> of the electromagnetic spectrum that contains radio waves, since radio waves have the lowest frequency of any of the other waves.</span>
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3 years ago
Which of these characteristics did all of the five waves of immigrants have in common A. They all had the same political beliefs
timofeeve [1]
I am pretty sure it is c
8 0
3 years ago
A tight knot can be easily opens by using a longer spanner. Give reasons
kobusy [5.1K]

It is because the effort distance is greater than the load distance

Explanation:

As we know, Effort×effort distance = load × load distance

So when effort distance is increases,

The effort decreases

So when the spanner’s handle is long

A tight knot can easily be opened by less effrot

I hope it helped

6 0
2 years ago
4) A cannon shoots a cannonball of mass 5kg vertically upward from the mouth of a cannon with muzzle velocity of 7 m/s. At a hei
Ad libitum [116K]

Answer:

h =220 m

Explanation:

Given that

u = 7 m/s

Even mass will attach but this will not produce any effect on the maximum height of the ball.Because in energy conservation the effect of mass does not present.

So the final speed of the ball will be zero at the maximum height.

v² = u² - 2 g (25 + h)

0 = 7² - 2 x 10 (25 +h)

49 = 20 ( 25 +h)

49 = 500 +20 h

Here h comes out negative that is why we are taking the 70 m/s in place of 7 m/s.

0 = 70² - 2 x 10 (25 +h)         ( take g =10 m/s²)

4900 = 20 ( 25 +h)

4900 = 500 +20 h

4900- 500 = 20 h

4400 = 20 h

440 = 2 h

h =220 m

5 0
3 years ago
A jogger runs by a river with a velocity of 7 m s relative to the ground. A leaf floating on the river moves with a velocity of
Hunter-Best [27]

Answer:

The velocity of the leaf relative to the jogger is 5 m/s.                    

Explanation:

Given that,

Velocity of jogger wrt to the ground, V_j=7\ m/s

velocity of leaf wrt the ground, v_i=2\ m/s

We need to find the velocity of the leaf relative to the jogger. Let it is equal to V. So, it is given by :

V=v_j-v_i\\\\V=7-2\\\\V=5\ m/s

So, the velocity of the leaf relative to the jogger is 5 m/s. Hence, this is the required solution.

3 0
3 years ago
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