Answer:
f = 632 Hz
Explanation:
As we know that for destructive interference the path difference from two loud speakers must be equal to the odd multiple of half of the wavelength
here we know that
given that path difference from two loud speakers is given as
now we know that it will have fourth lowest frequency at which destructive interference will occurs
so here we have
now for frequency we know that
Answer:
Answer:
The frequencies that the listener at P will hear a maximum intensity are: 85.75 Hz, 171.5 Hz, 257.25 Hz and 343 Hz.
Explanation:
Path Difference Δx is given as: nλ
where λ =
Δx can be re-written as: n×
where;
n = integer
v = speed of sound = 343 m/s
f = frequency
Δx = 19.0 m - 15.0 m
Δx = 4.0 m
f =
f = n × 85.75 Hz
Now; n = 1, 2, 3, 4 ; the frequencies that the listener at P will hear the maximum intensity will be
when n= 1
f = 1 × 85.75 Hz
f = 85.75 Hz
when n= 2
f = 2 × 85.75 Hz
f = 171.5 Hz
when n= 3
f = 3 × 85.75 Hz
f = 257.25 Hz
when n= 4
f = 4 × 85.75 Hz
f = 343 Hz
∴ the frequencies that the listener at P will hear the maximum intensity will be : 85.75 Hz, 171.5 Hz, 257.25 Hz and 343 Hz for n =1,2,3, and 4 respectively.