Ask question

Ask question

All categories

3 years ago

6

A pair of equal charges are separated by .75 m. There's a 2500 N force acting on them. What is the strength of the charge? Plz e

xplain how you got the answer too.

1 answer:

Natalija [7]3 years ago

8 0

Answer:

4.5643546 × 10^ -4

Explanation:

You might be interested in

It takes 6 seconds for a stone to fall to the bottom of a mine shaft. how deep is the shaft

Margaret [11]

You need the kinematic equation for distance as a function of acceleration:

$d = [v(initial) *t] + 0.5a*t^{2}$

where a = gravitational acceleration 9.8m/s^{2}
v(initial) = starting velocity
t = time of fall

if the stone started at rest then v(initial) = 0 making the equation simply $0.5a * t^{2}$

Let me know if you still need further help :)

6 0

3 years ago

A mercury barometer reads 745.0 mm on the roof of a building and 760.0 mm on the ground. Assuming a constant value of 1.29 kg/m3

Ipatiy [6.2K]

Answer:

The height of the building is 158.140 meters.

Explanation:

A barometer is system that helps measuring atmospheric pressure. Manometric pressure is the difference between total and atmospheric pressures. Manometric pressure difference is directly proportional to fluid density and height difference. That is:

$\Delta P \propto \rho \cdot \Delta h$

$\Delta P = k \cdot \rho \cdot \Delta h$

Where:

$\Delta P$ - Manometric pressure difference, measured in kilopascals.

$\rho$ - Fluid density, measured in kilograms per cubic meter.

$\Delta h$ - Height difference, measured in meters.

Now, an equivalent height difference with a different fluid can be found by eliminating manometric pressure and proportionality constant:

$\rho_{air} \cdot \Delta h_{air} = \rho_{Hg} \cdot \Delta h_{Hg}$

$\Delta h_{air} = \frac{\rho_{Hg}}{\rho_{air}} \cdot \Delta h_{Hg}$

Where:

$\Delta h_{air}$ - Height difference of the air column, measured in meters.

$\Delta h_{Hg}$ - Height difference of the mercury column, measured in meters.

$\rho_{air}$ - Density of air, measured in kilograms per cubic meter.

$\rho_{Hg}$ - Density of mercury, measured in kilograms per cubic meter.

If $\Delta h_{Hg} = 0.015\,m$ , $\rho_{air} = 1.29\,\frac{kg}{m^{3}}$ and $\rho_{Hg} = 13600\,\frac{kg}{m^{3}}$ , the height difference of the air column is:

$\Delta h_{air} = \frac{13600\,\frac{kg}{m^{3}} }{1.29\,\frac{kg}{m^{3}} }\times (0.015\,m)$

$\Delta h_{air} = 158.140\,m$

The height of the building is 158.140 meters.

5 0

3 years ago

Read 2 more answers

A runner hopes to complete the 10,000m run in less than 30,0min, after running at constant speed for exactly 27.0 min , there ar

tankabanditka [31]

Well I figured out at his current pace, he would finish the 1100 remaining meters in 200 seconds. However, he needs to complete it in 180 seconds. I'm not sure how to find out how long he has to accelerate at 0.20 m/s/s to complete it in 180 seconds.

3 0

3 years ago

A very low value of the equilibrium constant for a reaction can indicate that

slava [35]

That reactants are favored.

8 0

3 years ago

Which cars have the same magnitude of momentum? Check all that apply. car 1 car 2 car 3 car 4 car 5

wariber [46]

Answer:

Car 1 and Car 2 have the same momentum!

Explanation:

Using the formula of momentum (P=m*v), we get for each car:

Car 1: 5kg*2.2m/s = 11kg*m/s

Car 2: 5.5kg*2m/s = 11kg*m/s

Car 3: 6kg*1.35m/s = 8.1kg*m/s

Car 4: 6.5kg*1.9m/s = 12.35kg*m/s

Car 5: 7kg*1.25m/s = 8.75kg*m/s

7 0

3 years ago