Answer:
Step-by-step explanation:
let : x the length and y the width .... ( x > y and x ; y reals numbers )
the perimeter is : 2(x+y)
2(x+y) = 55...(1)
x/y = 7/4 ...(2)
by (2) : x = (7/4)y
subsct in (1) : 2( (7/4)y +y ) =55
(7/2)y +2y =55
multiply by 2
7y +4y = 110
11y = 110
y = 10
x = (7/4)(10)
x = 35/2
Answer:
it should be 5
Step-by-step explanation:
To eliminate the fraction, multiply by 2 both sides of the equation. This gives,
2A = h x (b1 + b2)
Then, divide both the left hand and the right hand side of the equation by the variable h.
2A / h = b1 + b2
Next, subtract b1 from both sides,
(2A / h) - b1 = b2
Rearranging the equation,
b2 = (2A/h) - b1
Here, Area of Square = a²
Area of parallelogram = a * b
Area of Trapezoid = (a+b)/2 * h
Area of Triangle = bh/2
In question, it says "half of the base" not bases, so most appropriate answer would be: Option D) Triangle
Hope this helps!
It’s gotta be c, trust me
