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Natali [406]
3 years ago
10

Use a model to divide. 1/4 ÷ 5 1/20 4/5 1 1/4 20

Mathematics
2 answers:
Marina CMI [18]3 years ago
5 0

Answer:

Just answered so they can get brainliest

Step-by-step explanation:

Lera25 [3.4K]3 years ago
3 0

Answer:

\frac{1}{4}  \div 5 \\  =  \frac{1}{20}

Pls....can mark brainliest

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ONLY ANSWER IF YOU'RE 100% SURE
FinnZ [79.3K]

Answer:

answer is 2

Step-by-step explanation:

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3 years ago
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Consider the linear expression 3x -15
Jobisdone [24]

Answer:

In linear expresiion 3 is the coefficient

X will be the variable and -15 will be the constant term.

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3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

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4 years ago
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3 years ago
What is the solution of √1-3x=x+3
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x = -1

Step-by-step explanation:

\sqrt{1-3x}=x+3\\\\1-3x=x^2+6x+9 \qquad\text{square both sides}\\\\x^2+9x+8=0 \qquad\text{put in standard form}\\\\(x+8)(x+1)=0 \qquad\text{factor}\\\\\left \{ {{x=-8} \atop {x=-1}} \right. \qquad\text{values that make the factors zero}

Only the solution x = -1 will work for this equation. The other solution is extraneous.

4 0
3 years ago
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