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3 years ago

Use a model to divide. 1/4 ÷ 5 1/20 4/5 1 1/4 20

Mathematics

2 answers:

Marina CMI [18]3 years ago

5 0

Answer:

Just answered so they can get brainliest

Step-by-step explanation:

Lera25 [3.4K]3 years ago

3 0

Answer:

$\frac{1}{4} \div 5 \\ = \frac{1}{20}$

Pls....can mark brainliest

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7th grade slow math help please !

natka813 [3]

Answer:

1/3

Step-by-step explanation:

= y2-y1/x2-x1

3-2/1+2

1/3

4 0

3 years ago

Read 2 more answers

At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion ring

andre [41]

Answer:

The number of onion rings is 3 in the combination meal and the number of sliders is 2 in the combination meal.

Step-by-step explanation:

Given:

At a particular restaurant, each onion ring has 65 calories and each slider has 250 calories. A combination meal with onion rings and sliders has a total of 5 onion rings and sliders altogether and contains 695 calories.

Now, to find the number of onion rings in the combination meal and the number of sliders in the combination meal.

Let the number of onion rings in the combination meal be $x.$

And let the number of sliders in the combination meal be $y.$

So, the total number of onion rings and sliders are:

$x+y=5\\\\y=5-x\ \ \ .....(1)$

Now, the total number of calories each onion rings and sliders has:

$x(65)+y(250)=695$

Substituting the value of $y$ from equation (1) we get:

$x(65)+(5-x)(250)=695\\\\65x+1250-250x=695\\\\1250-185x=695$

Subtracting both sides by 1250 we get:

$-185x=-555$

Dividing both sides by -185 we get:

$x=3.$

The number of onion rings in the combination meal = 3.

Now, substituting the value of $x$ in equation (1) we get:

$y=5-x\\\\y=5-3\\\\y=2.$

The number of sliders in the combination meal = 2.

Hence, the number of onion rings is 3 in the combination meal and the number of sliders is 2 in the combination meal.

8 0

3 years ago

Lily goes car shopping and finds two cars. The first one burns fossil fuel, gasoline, that sells for $18,000. It will cost $100

Anna007 [38]

Answer:

Cost to buy and run the first car for 5 years=$24000

Cost to buy and run the second car for 5 years=$26000

I think we should buy the first car, because It is cheaper to buy and maintain

Step-by-step explanation:

first car:

Cost $18000 to buy

Cost $100 to maintain each month

5years =5 x 12=60months

Cost to maintain for 60months=100x60=$6000

First car cost to buy and run over the 5 year period=18000+6000=$24000

Second car:

It cost $22400 to buy

Cost $60 to maintain each month

5years=60months

Cost to maintain for 60months is 60 x 60=$3600

Cost to buy and run over the second car for 5years is 22400+3600=$26000

4 0

4 years ago

Solve the exponential equation. (logs) 3(1.05)^x+1=6

Arte-miy333 [17]

$\bf 3(1.05)^x+1=6\implies 3(1.05)^x=5\implies (1.05)^x=\cfrac{5}{3}\\\\
-----------------------------\\\\
log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\qquad thus\\\\
-----------------------------\\\\
log\left[ (1.05)^x \right]=log\left( \cfrac{5}{3} \right)\implies xlog\left[ (1.05) \right]=log\left( \cfrac{5}{3} \right)
\\\\\\
x=\cfrac{log\left( \frac{5}{3} \right)}{log(1.05)}$

8 0

3 years ago

Find the area of the parallelogram when base = 10yd and height = 5yd. A. 15yd B. 15yd2 C. 50yd D. 50yd2

STALIN [3.7K]

area = l x w

10 * 5 = 50

answer is D. 50 yd^2

8 0

3 years ago