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AlladinOne [14]
3 years ago
13

PLEASE HELP!! I'LL GIVE YOU BRAINLIEST !!

Mathematics
1 answer:
Nostrana [21]3 years ago
3 0

Answer:

1.c

2.a

3.d

4.a

5.c

6.b

Step-by-step explanation:

sina=cos b

cosa= sin b

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M ∠abd=87 M ∠abd=9x-1 M ∠cbd =6x+58
elena-s [515]

Answer:

there is no answer to this

Step-by-step explanation:

4 0
3 years ago
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Find the line with the slope m=½ through point (8,1)​
Stels [109]

Answer:

y=\frac{1}{2}x-3

Step-by-step explanation:

y-y_1 =m(x-x_1 )\\
y-1=\frac{1}{2} (x-8)\\y=\frac{1}{2}x-3

4 0
2 years ago
You borrowed $25 from your friend. You paid him back in full after 6 months. He charged $2 for interest. What was the annual sim
Paraphin [41]
\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$2\\
P=\textit{original amount}\to& \$25\\
r=rate \\
t=years\to &\frac{1}{2}
\end{cases}

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solve for "r", you'd get a decimal amount, multiply times 100, to get the percentage form
5 0
3 years ago
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Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
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by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

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6 0
3 years ago
Which of the following arithmetic sequences have a common difference of ? -4,-1.5,1,3.5,6,8.5 1.5,3,4.5,6,7.5
zavuch27 [327]
F(x+1) = f(x) + 2.5 with f(x) is the current number.
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