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3 years ago

What is the decimal multiplier to decrease by 68%?

Mathematics

2 answers:

Brums [2.3K]3 years ago

6 0

Answer

Step-by-step explanation:

Novosadov [1.4K]3 years ago

5 0

Answer: .68

Step-by-step explanation: 68 percent in decimal form is .68 therefore you multiply a given number by .68 to decrease it by 68 percent

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Three more than the quotient of a number and 4 is equal to 8

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3 years ago

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mel-nik [20]

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2 years ago

Jon’s weekly salary was $1500. Find his new salary if he earned a 6% raise.

zepelin [54]

Answer:

$1590

Step-by-step explanation:

First, find 6% of $1500. Then add that amount to $1500.

To find a percent of a number, multiply the percent by the number. To change a percent to a decimal number, move the decimal point of the percent 2 places to the left. 6% as a decimal is 0.06

6% of $1500 =

= 6% * $1500

= 0.06 * $1500

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The raise is $90. Now we add $90 to $1500.

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6 0

4 years ago

Prove each statement that is true and ﬁnd a counterexample for each statement that is false. Assume all sets are subsets of a un

tekilochka [14]

Answer with Step-by-step explanation:

We are given that A, B and C are subsets of universal set U.

We have to prove that

$A\cap (B-C)=(A\cap B)-(A\cap C)$

Proof:

Let x $\in A\cap (B-C)$

Then $x\in A$ and $x\in(B-C)$

When $x\in ( B-C)$ then $x\in B$ but $x\notin C$

Therefore, $x\in( A\cap B)$ but $x\notin (A\cap C)$

Hence, it is true.

Conversely , Let $x\in(A\cap B)$ but $x\notin(A\cap C)$

Then $x\in A$ and $x\in B$

When $x\notin ( A\cap C)$ then $x\notin C$

Therefor, $x\in A\cap (B-C)$

Hence, the statement is true.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="latex-formula

Anastasy [175]

Answer:

x = 3 And x = - 14

Step-by-step explanation:

Given expression as :

$x^{2}+ 11x - 42 = 0$

Or, $x^{2}+ 14x - 3x - 42 = 0$

Or, x (x + 14) - 3 (x + 14) = 0

Or, (x + 14) (x - 3 ) = 0

I.e (x + 14 ) = 0 And (x - 3 ) = 0

∴ x = 3 And x = - 14 Answer

7 0

4 years ago