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4 years ago

6

Papers scattered randomly across the desk represents high entropy and are a good example of which law?

1 answer:

lord [1]4 years ago

8 0

<span>The second law of thermodynamics states that the entropy of any isolated system always increases.

So the paper tends to approach high entropy

Answer is C</span>

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What is the surface pressure of Venus?

kiruha [24]

answers 93 bar

The atmosphere of Venus is the layer of gases surrounding Venus. It is composed primarily of carbon dioxide and is much denser and hotter than that of Earth. The temperature at the surface is 740 K (467 °C, 872 °F), and the pressure is 93 bar (9.3 MPa), roughly the pressure found 900 m (3,000 ft) underwater on Earth.

3 0

3 years ago

. A bird is flying with a speed of 18.0 m/s over water when it accidentally drops a 2.00 kg fish. If the altitude of the bird is

zysi [14]

V^2 = u^2 + 2gr, where v - speed, u - initial speed=0, r - displacement (or height)
v^2 = 0 + 2*10*5.4
v = 10.2 m/s

4 0

3 years ago

Read 2 more answers

What is happening in the first part of this picture?

d1i1m1o1n [39]

Answer:

kenitic energy

Explanation:

6 0

3 years ago

Object A attracts object B with a gravitational force of 5 newtons from a given distance. If the distance between the two object

givi [52]

Answer:

Four times higher

Explanation:

F- G (m1 x m2)/ r^2

if r 1 = 2 and r 2 = 1 therefore F = G (m1 x m2)/ 1^2 is 4 times higher than

2^2 since G and m1 and m2 remained the same

5 0

3 years ago

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A 1400 kg car driving at 25 m/s slams on its brakes. The coefficient of kinetic friction between the tires and the road is 0.7.

tamaranim1 [39]

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

mass of the car, m = 1400 kg
Initial velocity of the car, u = 25 m/s
coefficient of kinetic friction, μ = 0.7

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

$F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s$

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

Learn more here:brainly.com/question/19887955

5 0

3 years ago