Answer:
Explanation:
We shall apply Bernoulli's formula to solve the problem . It is as follows .
P + ρ gh + 1/2 ρ v² = constant .
P₁ + ρ gh + 1/2 ρ v₁² = P₂ + ρ gh + 1/2 ρ v₂²
P₁ + 1/2 ρ v₁² = P₂ + 1/2 ρ v₂²
P₁ - P₂ = 1/2 ρ (v₂² - v₁² )
= .5 x 1,1 ( 30² - 20² )
= 275 N / m²
velocity over moon roof is high , pressure will be lower there by 275 N / m²
Given pressure difference already existing = 90500 - 90000 = 500 N / m²
Additional pressure difference due to velocity difference = 275 N / m²
Total pressure difference = 275 + 500 = 775 N / m²
Area of roof = .5 m²
Total force acting upwards on the roof
= .5 x 775 N
= 387.5 N .
Answer:
the total kinetic and potential energy of the ball is constant (mechanical energy remains the same)
Explanation:
As the ball falls, kinetic energy is increased in direct relation with the decrease in potential energy
ΔKE + ΔPE = 0
There are 3.3 feet in 1 meter, and 0.3 meters in 1 foot
123.561 square meters
Answer:
86.14 meters.
Explanation:
Step one:
Given data
velocity of car = 26 m/s
the coefficient of static friction between the tires and the road
µ = 0.4 (kinetic)
Let us take g = 9.81 m/s^2
Required
The distance x = distance in m
We know that
W = F*x (Work is force times distance)
Step two:
Conservation of energy gives
KE = W
Substituting gives
Solving for distance (x) gives
Simplifying
Substitute:
Therefore, the minimum braking distance is 86.14 meters.