Explanation:
Here,
Velocity of A=60km/hr
Velocity of B=80km/hr
Now,
Relative velocity of B with respect to A in the same direction=Velocity of B - Velocity of A
=80km/hr-60km/hr
=20km/hr
Answer:
K'=4K
Explanation:
The electric potential energy is given by :

Where
k is spring constant
x is compression or extension in the spring
If the displacement of a horizontal mass-spring system is doubled, x'= 2x
New elastic potential energy :

So, new elastic potential energy 4 times the initial elastic potential energy.
Answer:
Acceleration = 0.0282 m/s^2
Distance = 13.98 * 10^12 m
Explanation:
we will apply the energy theorem
work done = ΔK.E ( change in Kinetic energy ) ---- ( 1 )
<em>where :</em>
work done = p * t
= 15 * 10^6 watts * ( 1 year ) = 473040000 * 10^6 J
( note : convert 1 year to seconds )
and ΔK.E = 1/2 mVf^2 given ; m = 1200 kg and initial V = 0
<u>back to equation 1 </u>
473040000 * 10^6 = 1/2 mv^2
Vf^2 = 2(473040000 * 10^6 ) / 1200
∴ Vf = 887918.92 m/s
<u>i) Determine how fast the rocket is ( acceleration of the rocket )</u>
a = Vf / t
= 887918.92 / ( 1 year )
= 0.0282 m/s^2
<u>ii) determine distance travelled by rocket </u>
Vf^2 - Vi^2 = 2as
Vi = 0
hence ; Vf^2 = 2as
s ( distance ) = Vf^2 / ( 2a )
= ( 887918.92 )^2 / ( 2 * 0.0282 )
= 13.98 * 10^12 m
Answer:
OT
It is important to wear protective equipments during games and practices.
Explanation:
Practice is a review of what is about to happen in some time to come and with practice ,the future can be trusted.
During practice it is very important to use protective gears or equipments because without them, injuries and accidents are liable to occur.
During the major game it is also important to prevent accidents or big injuries as the equipments protect each vital part of the body.
Answer:
5.03 m
Explanation:
The wavelength of a wave is given by

where
v is the speed of the wave
f is the frequency of the wave
For the sonar signal in this problem,


Substituting into the equation, we find the wavelength:
