Answer:
Question 1)
a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.
This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,
where α is the angular acceleration.
In order to continue this question, the radius of the drums should be given.
Let us denote the radius of the drums as R, the angular acceleration of drum B is
α = 0.5/R.
b) The distance travelled by the drums can be found by the following kinematics formula:
One revolution is equal to the circumference of the drum. So, total number of revolutions is
Question 2)
a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:
b) 
Answer:
I = 6 A
Explanation:
Given that,
Power of an electric heatr, P = 1.38 kW
The voltage of the mains supply, V = 230 V
We need to find the current through the heater. The electric power in terms of voltage and current is given by :
So, the current through an electric heater is 6 A.
The atomic number of the atom is 13. This means that its electronic configuration is (2 8 3) or in other words:
1<span>s2, </span>2<span>s2, </span>2<span>p6, </span>3<span>s2, </span>3<span>p<span>1
If three electrons are lost, then these electrons are removed from the outermost level.
In our case, electrons are removed from the third energy level (one electron is removed from the 3p orbital and two electrons are removed from the 3s orbital).</span></span>
Answer:
A. To find the mass flow rate.
We use= 220 x 0.355/ 60
= 1.3kg/s
B. Volume flowrate is = mass flowrate / density
But density is 1000kg/m³
= 1.3kg/s/ 1000kg/m³
= 0.0013m³/s
C. Flow speead at 1
= 0.0013m³/s / (2 x 10-2m)²
= 6.5m/s
D.flow speed at 2
0.0013m³/s / (8x 10-2m)²
=1.63m/s
E. Gauge pressure at point 1
= 152+ 1/1000 ( 1.63)²- 6.5² + 1000( 9.8) ( 0-1.35)
= 119kpa
