A, because
rectangle- at least 1 angle should be 90 degrees.
square- all angles and sides should have the same measures.
quadrilateral- its any shape with 4 sides.
parallelogram-both pairs of opposite sides parallel and congruent.
rhombus-diagonals are perpendicular which means the angle of the perpendicular lines would be 90 degrees.
Answer: total cost = 36/w + 36/l + 9lw
Step-by-step explanation:
The formula for determining the volume of the rectangular box is expressed as
Volume = lwh
Where lwh represents the length, width and height of the box respectively.
Since the volume of the box = 3cm³,then
lwh = 3
h = 3/lw
Since the box is open, the surface area would be
2lh + 2wh + lw
Given that the material for the sides of the box costs 6 per square meter, the total cost for the sides is
(2lh × 6) + (2wh × 6)
Substituting h = 3/lw into the above expression, it becomes.
(2l × 3/lw × 6) + (2w× 3/lw × 6)
= 36/w + 36/l
Since the material for the bottom costs 9per square meter, the total cost for the bottom is
9 × lw = 9lw
Therefore, the total cost of the box as a function of the length land width is
36/w + 36/l + 9lw
Answer:
if 
Step-by-step explanation:
Given --> 
Substitute into the equation and solve for 
:
So, when 
Since segment AC bisects (aka cuts in half) angle A, this means the two angles CAB and CAD are the same measure. I'll refer to this later as "fact 1".
Triangles ABC and ADC have the shared segment AC between them. By the reflexive property AC = AC. Any segment is equal in length to itself. I'll call this "fact 2" later on.
Similar to fact 1, we have angle ACB = angle ACD. This is because AC bisects angle BCD into two smaller equal halves. I'll call this fact 3
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To summarize so far, we have these three facts
- angle CAB = angle CAD
- AC = AC
- angle ACB = angle ACD
in this exact order, we can use the ASA (angle side angle) congruence property to prove the two triangles are congruent. Facts 1 and 3 refer to the "A" parts of "ASA", while fact 2 refers to the "S" of "ASA". The order matters. Notice how the side is between the angles in question.
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Once we prove the triangles are congruent, we use CPCTC (corresponding parts of congruent triangles are congruent) to conclude that AB = AD and BC = BD. These pair of sides correspond, so they must be congruent in order for the entire triangles to be congruent overall.
It's like saying you had 2 identical houses, so the front doors must be the same. The houses are the triangles (the larger structure) and the door is an analogy to the sides (which are pieces of the larger structure).
