Question

Bruce drew a rectangle with a length of 8 3/4 inches and width of 6 inches. Brandon drew a rectangle with dimensions that were 1 1/2 times the dimensions of Bruce’s rectangle. What is the length of Brandon’s rectangle?

Answer 1

The correct answer is D.

Answer 2

Answer:

Option D. $13\frac{1}{8}$ inches

Step-by-step explanation:

Dimensions of the rectangle drawn by Bruce = $8\frac{3}{4}$ inches × 6 inches

or $\frac{35}{4}$ inches × 6 inches

Brandon drew a rectangle with dimension $(\frac{3}{2})$ times the dimension of Bruce's rectangle.

So scale factor of Brandon rectangle is $(\frac{3}{2})$.

So dimensions of Brandon's rectangle will be

Length = $\frac{35}{4}$ × scale factor

            = $\frac{35}{4}$ × $(\frac{3}{2})$

            = $\frac{105}{8}$

            = $13\frac{1}{8}$ inches

Option D. is the answer.