Answer:
1. 1/x = 8
Answer = 8x-1
2. 8x+1=3
Answer ; x=1/4
3. 7= 14/X
Answer ; x = 2
4.1/2x^2 = 2
Answer ;x=2
Step-by-step explanation:

Answers:
a = -6/37
b = -1/37
============================================================
Explanation:
Let's start things off by computing the derivatives we'll need

Apply substitution to get

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.
The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero
a-6b = 0
a = 6b
At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)
-6a -b = 1
-6(6b) - b = 1 .... plug in a = 6b
-36b - b = 1
-37b = 1
b = -1/37
Use this to find 'a'
a = 6b
a = 6(-1/37)
a = -6/37
There are two unknowns in this problem. To start, let's assign variables to each of them. Let x be the age of Jacob and y be the age of Isaiah. Then, we formulate equations based on the relationships stated.
x = 7 + y --> eqn 1
x + y = 63 --> eqn 2
Substituting eqn 1 to eqn 2, then solve for x and y:
(7+y)+y = 63
7 + 2y = 63
2y = 63 - 7
2y = 56
y = 56/2
y = 28
x = 28 + 7 = 35
Therefore, Jacob is 35 years old, and Isaiah is 28 years old.
Answer is 4.45 yeah it wrong