Answer:
f(x) = (x - 7)² - 14
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Standard Form: ax² + bx + c = 0
- Vertex Form: f(x) = a(bx - c)² + d
- Completing the Square: (b/2)²
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 14x + 63
<u>Step 2: Rewrite</u>
- Separate: f(x) = (x² - 14x) + 63
- Complete the Square: f(x) = (x² - 14x + 49) + 63 - 49
- Simplify: f(x) = (x - 7)² - 14
Okay! So 1/4 = 2/8 and 3/8 = 3/8 3/8+2/8= 5/8
3/8 is your answer
Answer:
2100
Step-by-step explanation:
28.34 rounds to 30
We look at the 8 which is greater than 5 and rounds the 2 to 3
69.72 rounds to 70
We look at the 9 which is greater than 5 and rounds the 6 to 7
30*70
2100
Answer:-1
Step-by-step explanation:
I rewrote it so it looks like this:
6y+6(1+3y)=-18
6y+6(1)+6(3y)=-18
6y+6+18y=-18
24y+6=-18
<u> -6 -6</u>
<u>24y</u>=<u>-24</u>
24 24
y=-1
we know that
For a polynomial, if
x=a is a zero of the function, then
(x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.
So
In this problem
If the cubic polynomial function has zeroes at 2, 3, and 5
then
the factors are

Part a) Can any of the roots have multiplicity?
The answer is No
If a cubic polynomial function has three different zeroes
then
the multiplicity of each factor is one
For instance, the cubic polynomial function has the zeroes

each occurring once.
Part b) How can you find a function that has these roots?
To find the cubic polynomial function multiply the factors and equate to zero
so

therefore
the answer Part b) is
the cubic polynomial function is equal to
