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iVinArrow [24]
3 years ago
11

The two legs of a right triangle are 9 and 40. how long is the third side

Mathematics
1 answer:
Sonbull [250]3 years ago
6 0
Refer to the diagram shown below.

Let x = the length of the third side (the hypotenuse) of the right triangle.
From the Pythagorean Theorem, obtain
x² = 9² + 40² = 81 + 1600 = 1681
x = 41

Answer:  41

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Rewrite the function by completing the square <br> f(x)=x^2-14x+63
Veseljchak [2.6K]

Answer:

f(x) = (x - 7)² - 14

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Vertex Form: f(x) = a(bx - c)² + d
  • Completing the Square: (b/2)²

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 14x + 63

<u>Step 2: Rewrite</u>

  1. Separate:                              f(x) = (x² - 14x) + 63
  2. Complete the Square:         f(x) = (x² - 14x + 49) + 63 - 49
  3. Simplify:                                f(x) = (x - 7)² - 14
8 0
3 years ago
Read 2 more answers
Joel made some muffins. He gave 1/4 of of the muffins to a neighbor. He took 3/8 of the muffins to school. What fraction of the
dolphi86 [110]
Okay!   So 1/4 = 2/8  and 3/8 = 3/8      3/8+2/8= 5/8
3/8 is your answer


6 0
3 years ago
Please do this ASAP!<br> No links !
Andreas93 [3]

Answer:

2100

Step-by-step explanation:

28.34 rounds to 30

We look at the 8 which is greater than 5 and rounds the 2 to 3

69.72 rounds to 70

We look at the 9 which is greater than 5 and rounds the 6 to 7

30*70

2100

7 0
3 years ago
How to solve -18=6y+6(1+3y)
slamgirl [31]

Answer:-1

Step-by-step explanation:

I rewrote it so it looks like this:

6y+6(1+3y)=-18

6y+6(1)+6(3y)=-18

6y+6+18y=-18

24y+6=-18

     <u> -6   -6</u>

<u>24y</u>=<u>-24</u>

24      24

y=-1

6 0
3 years ago
Read 2 more answers
Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.
TiliK225 [7]

we know that

For a polynomial, if x=a is a zero of the function, then (x−a) is a factor of the function. The term multiplicity, refers to the number of times that its associated factor appears in the polynomial.

So

In this problem

If the cubic polynomial function has zeroes at 2, 3, and 5

then

the factors are

(x-2)\\ (x-3)\\ (x-5)

Part a) Can any of the roots have multiplicity?

The answer is No

If a cubic polynomial function has three different zeroes

then

the multiplicity of each factor is one

For instance, the cubic polynomial function has the zeroes

x=2\\ x=3\\ x=5

each occurring once.

Part b) How can you find a function that has these roots?

To find the cubic polynomial function multiply the factors and equate to zero

so

(x-2)*(x-3)*(x-5)=0\\ (x^{2} -3x-2x+6)*(x-5)=0\\ (x^{2} -5x+6)*(x-5)=0\\ x^{3} -5x^{2} -5x^{2} +25x+6x-30=0\\ x^{3}-10x^{2} +31x-30=0

therefore

the answer Part b) is

the cubic polynomial function is equal to

x^{3}-10x^{2} +31x-30=0

7 0
2 years ago
Read 2 more answers
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