Answer:
Option B and C is correct
Step-by-step explanation:
<h3><u>Given</u>;</h3>
- Priya has 5 pencils, each x inches in length.
- Total length = 34.5 inches.
Now,
5 times x = 34.5
So,
5x = 34.5
34.5 ÷ 5 = x
Thus, 5x = 34.5 and 34.5 ÷ 5 = x are the answer
<u>-TheUnknownScientist 72</u>
Okay so, togo flies 30 miles in 3/5 of an hour with the wind.togo flies 30 miles in 5/6 of an hour against the wind. his rate of speed with the wind was 30 / (3/5) = 30*5/3 = 150/3 = 50 mph.his rate of speed against the wind was 30 / (5/6) = 30*6/5 = 6*6 = 36 mph.3/5 of an hour times 50 mph = 30 miles.
5/6 of an hour times 36 mph = 30 miles.mph looks good.
going he was with the wind.
his rate of speed then was the airplane speed plus the wind speed.coming back he was against the wind.his rate of speed then was the airplane speed minus the wind speed.-----50 mph = A + W36 mph = A - W-----looks like A + W - (A - W) should equal 50 - 36.removing parentheses, equation becomesA + W - A + W = 14.
combining like terms, the equation becomes2*W = 14.dividing both sides by 2, equation becomesW = 7.if W = 7, then A can be found as follows:50 = A + 7A = 43.likewise,36 = A - 7A = 43.since the airplane speed is the same, it looks like the answer is good.solving in the original equations, we get3/5 * (43 + 7) = 303/5 * 50- = 3030 = 30good.-----5/6 * (43 - 7) = 305/6 * 36 = 3030 = 30good.
answer is W = 7 and A = 43.
A mixed number is a combination of a whole number and a fraction, so in this case we have 8 as the whole part and 0.45 as the fraction, 0.45 is equal to 45/100, and that fraction can be simplified as well, lets see:
8.45 = 8 45/100
= 8 9/20
Answer:
First we need to calculate the distance between Clifton and Burlington by using Pythagorean theorem:
x² + 65² = 97²
=> x² = 97² - 65²
=> x² = 5184
=> x = √5184 = 72 (m)
The total distance from Aurora to Clifton through Burlington is: 65 + 72 = 137 (m)
We have: 137 - 97 = 40 (m)
So it is 40 m closer to travel from Aurora to Clifton directly than from Aurora to Clifton through Burlington
X^4 + x^3 + x^2 + x = 0
x(x^3 + x^2 + x + 1) = 0
x[x^2(x + 1) + 1(x + 1)] = 0
x(x + 1)(x^2 + 1) = 0 ⇔ x = 0 or x + 1 = 0 or x^2 + 1 = 0
x = 0 or x = -1 or x^2 = -1 -false
Answer: x= 0 or x = -1.
