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Nadusha1986 [10]
3 years ago
12

PLEASE HELP!!

Mathematics
2 answers:
beks73 [17]3 years ago
8 0
<span>Let x = the width
:
It says,"The length of a rectangle is 4 less than 3 times the width." write that as:
L = 3x - 4
:
If the perimeter is 40, find the dimensions of the rectangle.
:
We know: 2L + 2W = 40
:
Substitute (3x-4) for L and x for W
2(3x-4) + 2x = 40
:
6x - 8 + 2x = 40; Multiplied what's inside the brackets
:
6x + 2x = 40 + 8; do some basic algebra to find x; (added 8 to both sides)

:
8x = 48
:
x = 48/8
:
x = 6 which is the width
:
It said that L = 3x - 4, therefore:
L = 3(6) - 4
L = 18 - 4
L = 14; is the length
:
Check our solutions in the perimeter:
2(14) + 2(6) =
28 + 12 = 40</span>
Arada [10]3 years ago
4 0
Length= 3x-4
width= x
perimeter= 72 feet
2(3x-4)+2x=72
6x-8+2x=72
8x-8=72
8x=80
x=10
The width is 10 and the length is 26.

Hope this helps!
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Answer:

40.2

Step-by-step explanation:

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3 years ago
Which statements about residuals are true for the least-squares regression line? I. A random scattering of residuals indicates t
Daniel [21]

Answer:

II. The sum of the residuals is always 0.

Step-by-step explanation:

A least squares regression line is a standard technique in regression analysis used to make the vertical distance obtained from the data points running to the regression line to become very minimal or as small as possible.

For any least-squares regression line, the sum of the residuals is always zero.

Basically, residuals are used to measure or determine whether or not the line of regression is a good fit or match for the data by subtracting the difference between them i.e the predicted y value and the actual y value, for the x value respectively.

Hence, the statement about residuals which is true for the least-squares regression line is that the sum of the residuals is always zero (0).

7 0
3 years ago
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djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
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\frac{n^{2}-6 }{n^{2}-2 }
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5 0
4 years ago
Read 2 more answers
5 hours 15 min + 3 hours 33 min<br><br><br> show the working as well
Alika [10]

Answer:

8 hours 48 mins

Step-by-step explanation:

  h  m

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+3:33

--------------

  8:48

or

5 hours + 3 hours =8 hours,

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Therefore, it's 8 hours 48 mins.

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~zaro~

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