Lagrange multipliers:







(if

)

(if

)

(if

)
In the first octant, we assume

, so we can ignore the caveats above. Now,

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of

.
We also need to check the boundary of the region, i.e. the intersection of

with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force

, so the point we found is the only extremum.
Answer:
64x+56 & 24x+56
Step-by-step explanation:
I hope this is what you mean because this is not an equation as it is not set equal to anything.
Both problems solved by distributive property -
8*8x + (8*7) = 64x+56
8*3x + (8*7) = 24x+56
Answer:
x=-5
Step-by-step explanation
The first box has eight x's and six 1's which means that it would be written as 8x+6
The second box has four x's and fourteen -1's which means that it would be written as 4x-14
You set them equal to one another
8x+6=4x-14
You subtract 4x from both sides
4x+6=-14
Subtract 6 on both sides
4x=-20
Divide 4 on both sides
x=-5
Hope it helps :))
The initial investment was 3.03 because this is the value that does not change and comes before the value with the exponent "2x" is mentioned.