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vodomira [7]
3 years ago
14

Using polynomial identities, multiply the expression (2x+8y)(2x-8y)

Mathematics
1 answer:
igomit [66]3 years ago
3 0
(2x)sqrt 2- 64y2 is the answer
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ser-zykov [4K]

Answer:

dfhjkbfgv u u u ucuvvcuvuvuc y y y y y y y y y h u h h u u h h h h uu uu u u uu

5 0
3 years ago
the price of a technology stock was $9.53 yesterday. Today, the price rose to $9.66. Find the percentage increase. Round your an
galben [10]
So, 9.66 - 9.53 will then be 0.13, so if we take 9.66 to be the 100%, what is 0.13 off of it in percentage then?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
9.66&100\\
0.13&p
\end{array}\implies \cfrac{9.66}{0.13}=\cfrac{100}{p}\implies p=\cfrac{0.13\cdot 100}{9.66}
6 0
3 years ago
people with a college education: A.are always more successful than those without one. B.have increased personal and professional
Fynjy0 [20]

Answer:

Hey there!

The correct answer is A. People with a college education are always more successful than those without one. You learn important skills in college that are simply impossible to even know about in high school and middle school.

Let me know if this helps :)

8 0
3 years ago
Read 2 more answers
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
59 points on this! Pls answer
joja [24]

Answer:

(a) y = -4x + 4   (b) y = 2x + 3

<u>solving steps:</u>

note: m refers to slope and y₁ to y point and x₁ to x point

a)

coordinates: (2,-4)

slope: -4

equation:

  • y - y₁ = m(x - x₁)
  • y - -4 = -4(x-2)
  • y = -4x + 8 - 4
  • y = - 4x + 4

b)

coordinates: (1,5), (-1,1)

slope:  \sf \dfrac{y-y_1}{x-x_1}  

  • \sf \dfrac{1-5}{-1-1}  
  • 2

equation:

  • y - y₁ = m(x - x₁)
  • y - 5 = 2(x - 1)
  • y - 5 = 2x - 2
  • y = 2x - 2 + 5
  • y = 2x + 3
5 0
2 years ago
Read 2 more answers
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