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vodomira [7]
3 years ago
14

Using polynomial identities, multiply the expression (2x+8y)(2x-8y)

Mathematics
1 answer:
igomit [66]3 years ago
3 0
(2x)sqrt 2- 64y2 is the answer
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Solve for q. -5(3-q) +4=5q-11
soldier1979 [14.2K]

Perform the indicated multiplication first:  -15 + 5q + 4 = 5q - 11

Note that 5q appears on both sides of this equation.  Cancelling, we get :

-11 = -11.  This is always true.  Thus, -5(3-q) +4=5q-11 is true for all q.

4 0
3 years ago
3(7v-5)-v(10v-9) how do is solve this problem
Alika [10]

3(7v-5)-v(10v-9) = 21v - 15 -10v² + 9v = - 10v² + 30v - 15

8 0
3 years ago
Plz answer this correctly to get more points
crimeas [40]

Answer: x = 30°

Concept:

Here, we need to know the idea of an isosceles triangle and the vertical angle theorem.

An <u>isosceles triangle</u> is a triangle that has any two of its sides equal to each other. Also, the angles opposite these equal sides are equal, which is basically the base angles.

The <u>vertical angle theorem</u> states that two vertical angles formed when two lines intersect each other are always equal to each other.

Solve:

<u>Find the other base angle of the isosceles triangle.</u>

Since there are two equal sides, we know that this is an isosceles triangle.

Since the definition said that the base angles are equal, the other base angle would also be x.

<u>Find the value of x</u>

According to the vertical angle theorem, two vertical angles formed by intersection are equal.

Just as angle x and 30°, are vertical angles formed by intersection, therefore, \boxed{x=30}

Hope this helps!! :)

Please let me know if you have any questions

8 0
3 years ago
Simplify 1.25 (-x -4)
statuscvo [17]

Answer:

1.25(-xsquare - 8x + 16)

Step-by-step explanation:

pls give me brainliest

I'm not sure but I think so

3 0
2 years ago
The polynomial equation x^3-4x^2+2x+10=x^2-5x-3 has complex roots 3+-2i What is the other root? Use a graphing calculator and a
kirill115 [55]

Answer:

B. -1

Step-by-step explanation:

x^3-4x^2+2x+10=x^2-5x-3

We know it has 3 roots since it is a 3rd degree polynomial.

Two of the roots are (3+2i) and (3-2i)

Subtract x^2-5x-3 from both sides

x^3-4x^2+2x+10-(x^2-5x-3)=x^2-5x-3 -(x^2-5x-3)

Distribute the minus sign

x^3-4x^2+2x+10-x^2+5x+3=x^2-5x-3 -x^2+5x+3

x^3 -5x^2+7x +13 =0

Graphing this equation , we see that it crosses the x axis at x=-1

That covers the three roots, 1 real and two complex

7 0
3 years ago
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