Step-by-step explanation:
Hey there!!!
Here,
Given, A line passes through point (2,-2) and is perpendicular to the y= 5x+2.
The equation of a straight line passing through point is,

Now, put all values.

It is the 1st equation.
Another equation is;
y = 5x +2........(2nd equation).
Now, Comparing it with y = mx + c, we get;
m2=5
As per the condition of perpendicular lines,
m1×m2= -1
m1 × 5 = -1
Therefore, m2= -1/5.
Keeping the value of m1 in 1st equation.

Simplify them.



Therefore the required equation is x+5y+8= 0.
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
If width is w the length can be represented as 5/2+2w.
Formula for perimeter is 2l + 2w
So it would be 2w + 2(5/2 + 2w)
OR 2w + 5 + 4w
OR 6w + 5
See if this helps ;)
Answer:
y = (7/3)x - 9
Step-by-step explanation:
1. Convert given equation to y=mx+b form --> y = (7/3)x - 5/3
2. Equation of new line --> y = (7/3)x + b
- Note: 7/3 is the slope and for lines to be parallel they need the same slope so both equations have 7/3.
3. Plug in given values --> 5 = (7/3)(6) + b
4. Solve for b --> b = 5 - 14 b = -9
5. New line --> y = (7/3)x - 9
Answer:c)21
Step-by-step explanation:
i just took the quiz
Use a factor<span> tree to express </span>60<span> as a </span>product<span> of prime </span>factors<span>. So the prime factorization of </span>60<span> is 2 × 2 × 3 × 5, which can be written as 2 </span>2<span> × 3 × 5.</span>