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3 years ago

Find the slope-intercept form of the equation of the line that passes through (-5,3) and is parallel to 12x-3y=10

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

3 0

Answer:

y=4x+23

Step-by-step explanation:

Convert given equation into slope-intercept form:

12x-3y=10

4x-y=10/3

-y=10/3-4x

y=-10/3+4x

y=4x-10/3

Because the new equation must be parallel to the old equation, the slope stays the same, but the y-intercept changes based on the point that the new equation should pass through:

y=4x+b

3=4(-5)+b

3=-20+b

23=b

This means the slope-intercept form of the equation of the line that passes through (-5,3) and is parallel to 12x-3y=10 is y=4x+23

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Read 2 more answers

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

Rzqust [24]

Answer:

a = 6 or 9

Step-by-step explanation:

The "a", "b", and "c" of the quadratic formula are the coefficients of a², a, and the constant term in the given equation:

... a = 2, b = -30, c = 108

Then the quadratic formula tells you the solutions are ...

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_____

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... The solution to pa² +qa +r = 0 is ... a = (-q ± √(q²-4pr))/(2p)

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3 years ago

Identify the vertex of the quadratic function in standard form y=2x^2 -16x+31

lapo4ka [179]

Answer:

(4,1)

Step-by-step explanation:

The vertex of the quadratic can be found using -b/2a. The vertex is the point (-b/2a, f(-b/2a)).

To find the x coordinate of the quadratic, define its a,b, and c. The quadratic has a = 2, b=-16, and c=31. Then -b/2a is -(-16)/2(2) = 16/4 = 4.

To find the y-coordinate, input the x=4 and solve for y.

$y=2(4)^2-16(4)+31\\y=2(16)-64+31\\y=32-64+31\\y=1$

The vertex is (4,1).

8 0

3 years ago

Given that f(x)=x-3 and g(x)=x^2-x, find (f+g)(-2)

mario62 [17]

Answer:

(f + g)(- 2) = 1

Step-by-step explanation:

(f + g)(x) = f(x) + g(x) , thus

f(x) + g(x)

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= x² - 3

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(f + g)(- 2) = (- 2)² - 3 = 4 - 3 = 1

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3 years ago