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frozen [14]
3 years ago
14

3) PLEASE HELP ME WITH THIS QUESTION, [

email protected]!!!!!! WILL MARK BRAINLIEST + 10 POINTS :D

Mathematics
1 answer:
irga5000 [103]3 years ago
5 0
Asymptotes at -(infinity) and 4
☺☺☺☺
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The local amusement park was interested in the average wait time at their most popular roller coaster at the peak park time (2 p
Effectus [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data:

118, 124, 108, 116, 99, 125, 138, 118, 119, 121, 65, 130, 120

Ordered data:

65, 99, 108, 116, 118, 118, 119, 120, 121, 124, 125, 130, 138

1.)

90th percentile :

0.9(n + 1)th term

n = sample size = 13

0.9(14) th term

= 12.6th term

= (12 + 13)th / 2

= (130 + 138) / 2

= 134

Third quartile (Q3) = 75th percentile

0.75(n + 1)th term

n = sample size = 13

0.75(14) th term

= 10.5th term

= (10 + 11)th / 2

= (124 + 125) / 2

= 124.5

What is the first quartile?

First quartile (Q1) :

0.25(n + 1)th term

n = sample size = 13

0.25(14) th term

= 3.5th term

= (3 + 4)th / 2

= (108 + 116) / 2

= 112

(4) What is the 10th percentile?

0.1(n + 1)th term

n = sample size = 13

0.1(14) th term

= 1.4th term

= (1 + 2)th / 2

= (65 + 99) / 2

= 82

(5) 65tb percentile :

0.65(n + 1)th term

n = sample size = 13

0.65(14) th term

= 9.1th term

= (9 + 10)th / 2

= (121 + 124) / 2)

= 122.5

(6) What is the IQR?

Q3 - Q1

124.5 - 112

= 12.5

(7) What are the lower and upper limits?

Maximum = 138

Minimum = 65

4 0
2 years ago
What is the solution to the equation 41/5 =15-(2x+3)
likoan [24]
\frac{41}{5}=15-(2x+3) \\\\ \frac{41}{5}=15-2x-3 \\\\ \frac{41}{5}=12^{(5}-2x^{(5} \\\\ 41=60-10x \\\\ 41-60=-10x \\\\ -19=-10x \\\\ 19=10x \\\\ \boxed{x=\frac{19}{10}}
4 0
3 years ago
Read 2 more answers
Simplify y3x6 / y5x4 for sum
Xelga [282]
9/10 or 0.9
Hope this helps
6 0
3 years ago
The co-ordinate of point P is (x+3) and Q is (x-3). Then find d(P,Q). If coordinate of R is (x+2). Find d(Q,R).
kari74 [83]

Answer:

<h2>d(P, Q) = 6</h2><h2>d(Q, R) = 5</h2>

Step-by-step explanation:

The formula of a distance between two points A(a) and B(b):

<h3>d = |b - a|</h3>

We have P(x + 3), Q(x- 3), R(x + 2).

Substitute:

d(P, Q) = |(x - 3) - (x + 3)| = |x - 3 - x - 3| = |-6| = 6

d(Q, R) = |(x + 2) - (x - 3)| = |x + 2 - x - (-3)| = |2 + 3| = |5| = 5

5 0
3 years ago
Which translation vectors could have been used for the pair of figures?
Ierofanga [76]

if set up like

1 2

3 4

5 6

it would be 4 and 6

7 0
3 years ago
Read 2 more answers
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