The ABO blood groups in humans are expressed as the IA, IB, and i alleles. The IA allele encodes the A blood group antigen, IB e
ncodes B, and i encodes O. Both A and B are dominant to O. If a heterozygous blood type A parent (IAi) and a heterozygous blood type B parent (IBi) mate, one quarter of their offspring are expected to have the AB blood type (IAIB) in which both antigens are expressed equally. a) What other genotypes will be found? Show your work in a Punnett square.
1 answer:
Answer:
Apart from AB-type, other genotypes that would be formed will be A- blood type, B- blood type and O-blood type (the probability for each genotype is one-quarter )
Explanation:
As the parents are heterozygous in blood type, the gametes formed will be of IA, IB and i types, and thus the formed genotypes A- blood type, B- blood type and O-blood type will have same probability as that of AB-type.
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A statement which best supports the choice made in Part A (independent assortment) is: C. The diagram shows four unique gametes that are the result of two chromosomes separating in different ways.
<h3>Mendel's law of independent assortment.</h3>Mendel's law of independent assortment is a theory which states that the alleles of two or more different genes are sorted into unique gametes that are independent of each another.
This ultimately implies that, the allele that is typically being received by a gamete for one gene doesn't influence or affect the type of allele that is received for another gene.
Based on the biological process (independent assortment) shown in the image attached below for part A, we can infer and logically deduce that a statement which best supports the choice made is that he diagram shows four unique gametes that are the result of two chromosomes separating in different ways.
Read more on independent assortment here: brainly.com/question/2376592
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