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Alexus [3.1K]
2 years ago
12

Buns,cost 40p each. Cakes cost 55p each. I spend exactly £4.35 on buns and cakes.

Mathematics
2 answers:
mart [117]2 years ago
7 0

40p + 55p = 95p

435p ÷ 95p = 4.57...

So, the sum of the two pairs can go into £4.35 four times.

That meant if I increase the buns & cakes four times, it will help me get closer to the sum of £4.35 & work out which was extra

(40 x 4 = 160) & (55 x 4 = 220)

160 + 220= 380p or £3.80

Adding them up I get 380 pence & that's 55p short to getting to the sum of 435p or £4.35

(435-380=55p)

Thus, the extra is the cake, meaning you bought 4 buns and 5 cakes.

Hope this helps!

horsena [70]2 years ago
4 0

By solving a linear equation, we conclude that you bought 4 buns and 5 cakes.

<h3>How many of each did I buy?</h3>

We will define the two variables:

  • x = number of buns bought.
  • y = number of cakes bought.

We know that you spent exactly £4.35, then we only need to solve the linear equation:

x*0.40 + y*0.55 = 4.35

We need to solve that equation for x and y, such that the values of x and y can only be positive whole numbers.

We can rewrite the equation as:

y*0.55 = 4.35 - x*0.40

y = (4.35 - x*0.40)/0.55

Now we only need to evaluate it in different values of x, and see for which value of x, the outcome y is also a whole number.

We will see that for x = 4, we have:

y = (4.35 - 4*0.40)/0.55 = 5

So you bought 4 buns and 5 cakes.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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Troyanec [42]

Answer:

153 adults and 168 children

Step-by-step explanation:

x - number of adults

y - number of children

\left \{ {{6x + 4y = 1590} \atop {x + y = 321}} \right.

\left \{ {{6x+4y = 1590} \atop {x=321-y}} \right.

\left \{ {{6*(321 - y)+4y = 1590} \atop {x=321-y}} \right.

\left \{ {{1926 -6y+4y=1590} \atop {x=321-y}} \right.

\left \{ {{1926 -2y=1590} \atop {x=321-y}} \right.

\left \{ {{-2y=1590-1926} \atop {x=321-y}} \right.

\left \{ {{-2y=-336} \atop {x=321-y}} \right.

\left \{ {{y=168} \atop {x=321-y}} \right.

\left \{ {{y=168} \atop {x=321-168}} \right.

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Is it all clear?

6 0
3 years ago
Hey can you please help me posted picture of question
dangina [55]
The solutions to the given quadratic equation can be determined using quadratic formula.

x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}

b =coefficient of x term = -1
a = coefficient of squared term = 4
c = constant term = 9

Using the values in the above formula we get:

x= \frac{1+- \sqrt{1-4(4)(9)} }{2(4)}  \\  \\ &#10;x= \frac{1+- \sqrt{-143} }{8}  \\  \\ &#10;x= \frac{1+-i \sqrt{143} }{8}

So, option D gives the correct answers


4 0
3 years ago
Naoya read a book cover to cover in a single session, at a rate of 555555 pages per hour. After 444 hours, he had 350350350 page
natali 33 [55]

Answer:

y=-55x+570

Step-by-step explanation:

The correct question is

Naoya read a book cover to cover in a single session, at a rate of 55 pages per hour. After 4 hours, he had 350 pages left to read.

Let y represent the number of pages left to read after x hours.

Complete the equation for the relationship between the number of pages left and number of hours.

Let

x -----> the time in hours

y ----> the number of pages left to read

we know that

The linear equation in point-slope  form is equal to

y-y1=m(x-x1)

In this problem we have

m=-55\frac{pages}{hour}  ----> is negative because the linear function is decreasing

point\ (4,350)

substitute

y-350=-55(x-4)

y-350=-55x+220

y=-55x+220+350

y=-55x+570

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4 years ago
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uranmaximum [27]

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Step-by-step explanation: You need to do 6.56/4 which is 1.64

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