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3 years ago

1. Describe the pattern in each sequence. Then find the next two terms of

Mathematics

1 answer:

dalvyx [7]3 years ago

5 0

Answer:

a b c

Step-by-step explanation:

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(7x – 8) + (3X + 8) = 180 x=

GenaCL600 [577]

Step-by-step explanation:

I have answered ur question

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2 years ago

A rectangular image of length 5 cm and width 7 cm is magnified in a studio. On magnification, 1 cm of the image represents 15cm.

Andre45 [30]

Answer:

238 cm

Step-by-step explanation:

so we have a scale factor of 17: 1

originally we had the dimensions: 3cm by 4m

now we have 3*17 by 4*17 = 51 cm by 68 cm

Perimeter = 2*51 + 2*68 = 238 cm

8 0

1 year ago

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The fourth-grade students at Harvest School make up 0.3 of all students at the school. Witch fraction is equivalent to 0.3? -Zya

Leni [432]

3/10 or three tenths

4 0

2 years ago

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Line A passes through the points (1, -1) and (-2, 8).

Viefleur [7K]

The answer to this question will be D

5 0

2 years ago

Need answer to 4 and 5

algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3$ = 6

$g_3 = 2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9$ = 18

$g_4 = 2 . 3^{4 - 1} = 2 . 3^{3} = 2 . 27$ = 54

$g_5 = 2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81$ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $t_n = \frac{2}{3}t_{n - 1}$

$t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1 = \frac{2}{3}6$ = 4

$t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3}$

$t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9}$

$t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27}$

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

8 0

3 years ago