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Westkost [7]
3 years ago
15

Tickets to a movie cost $7.25 for adults and $5.50 for students. A group of friends purchased 8 tickets for $52.75. How many adu

lt tickets were purchased?
Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0
Using systems of equations, you can find the number of tickets by elimination.
S are students and A are adults.
S+A=8
7.25A+5.50S=52.75
Multiply the first equation by -5.50 to eliminate S.
-5.50A-5.50S=-44
7.25A+5.50S=52.75
1.75A=8.75
8.75÷1.75=5
There were 5 adult tickets and 3 students.
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Figure ABCD - Figure EFGH
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<h3><u>Answer:</u></h3>
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<h3><u>Step-by-step explanation:</u></h3>

We know that:

  • <u>Trapezoid ABCD has one side that is 25 unit. </u>
  • <u>The other 3 sides (AB, BC, and CD) are 12 units. </u>
  • <u>EF = 6 units</u>
  • <u>EH = 12.5</u>
  • <u>Trapezoid ABCD is congruent to Trapezoid EFGH</u>

<em>If the 3 sides of the trapezoid ABCD are the same sides, then side EF, FG, GH must be of the same length because of congruence. The value of FG and GH must be the same length as EF. We can clearly see in the picture that EF is 6 units. Hence, EF is 6 units, FG is 6 units, and GH is 6 units. The work of the perimeter is shown below.</em>

<u>Work</u>

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