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Westkost [7]
3 years ago
15

Tickets to a movie cost $7.25 for adults and $5.50 for students. A group of friends purchased 8 tickets for $52.75. How many adu

lt tickets were purchased?
Mathematics
1 answer:
Aleks04 [339]3 years ago
4 0
Using systems of equations, you can find the number of tickets by elimination.
S are students and A are adults.
S+A=8
7.25A+5.50S=52.75
Multiply the first equation by -5.50 to eliminate S.
-5.50A-5.50S=-44
7.25A+5.50S=52.75
1.75A=8.75
8.75÷1.75=5
There were 5 adult tickets and 3 students.
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Kamrynn is looking at her five quiz scores of 96 90 94 93 and 90. Determine the mean rounded to the nearest tenth median mode an
Romashka [77]

Answer:

Mean = 90, Median = 93, Mode = 90, Range = 6

Step-by-step explanation:

Mean:

96 + 90 + 94 + 93 + 90 = 463

463 ÷ 5 = 92.5

92.5 to nearest tenth = 90

Mean = 90

Median:

<em>90, 90</em>, <u>93</u>, <em>94 ,96</em>

Median = 93

Mode

<em>96, </em><u>90</u><em>, 94, 93, </em><u>90</u><em> </em>

Mode = 90

Range:

96 - 90 = 6

Range = 6

8 0
2 years ago
If 2 + 2^2 + 2^3 +...+ 2^n = 510 then n = ?
jonny [76]

Answer:

N= 8

Step-by-step explanation:

5 0
2 years ago
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The length of a banquet table is 4 feet longer than 6 times its width. If the perimeter is 78 feet, what are the dimensions of t
harina [27]
Hello,
2(l+w)=78
Divided 2 from both side
2(l+w)/2=78/2
l+w=39 feet

l=6w+4
Replace l with 6w+4

6w+4+w=39
7w+4=39
Subtract 4 from both side
7w=35
Divided 7 from both side
w=5 feet
l=6w+4
l=6(5)+4
l=30+4
l=34 feet. As a result, the length of the rectangle is 34 feet and the width of rectangle is 5 feet. Hope it help!
7 0
3 years ago
A rectangular storage container with a lid is to have a volume of 2 m3. The length of its base is twice the width. Material for
Scilla [17]

Answer:

Dimensions are 2 m by 1 meter by 1 meter,

Minimum cost is $ 18.

Step-by-step explanation:

Let w be the width ( in meters ) of the container,

Since, the length is twice of the width,

So, length of the container = 2w,

Now, if h be the height of the container,

Volume = length × width × height

2 = 2w × w × h

1 = w² × h

\implies h=\frac{1}{w^2}

Since, the area of the base = l × w = 2w × w = 2w²,

Area of the lid = l × w = 2w²,

While the area of the sides = 2hw + 2hl

= 2h( w + l)

= 2\times \frac{1}{w^2}(w+2w)

=\frac{6w}{w^2}

=\frac{6}{w}  

Since, Material for the base costs $1 per m². Material for the sides and lid costs $2 per m²,

So, the total cost,

C(w) = 1\times 2w^2+2\times 2w^2 + 2\times \frac{6}{w}

=2w^2+4w^2+\frac{12}{w}

=6w^2+\frac{12}{w}

Differentiating with respect to w,

C'(w) = 12w -\frac{12}{w^2}

Again differentiating with respect to w,

C''(w) = 12 + \frac{24}{w^3}

For maxima or minima,

C'(w) = 0

\implies 12w -\frac{12}{w^2}=0

\implies 12w^3 - 12=0

w^3-1=0\implies w = 1

For w = 1, C''(w) = positive,

Hence, for width 1 m the cost is minimum,

Therefore, the minimum cost is C(1) = 6(1)²+12 = $ 18,

And, the dimension for which the cost is minimum is,

2 m by 1 meter by 1 meter.

7 0
3 years ago
Please help me......​
Scilla [17]

Answer:

-1/4

Step-by-step explanation:

I'm not sure what exactly you needed. But this is the slope of the line. Hope this helps! Have a great day! :)

3 0
3 years ago
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