I dont get it im confusid here
Answer:
a square pyramid
Step-by-step explanation:
its easy ;)
Answer:
thxxxx
Step-by-step explanation:
Answer:
He didn't calculate the b-value correctly.
Step-by-step explanation:
The given parent function is:
![y = \cot(x)](https://tex.z-dn.net/?f=y%20%3D%20%20%5Ccot%28x%29%20)
The transformation is of the form:
![y =a \cot(bx + c) + d](https://tex.z-dn.net/?f=y%20%3Da%20%20%5Ccot%28bx%20%2B%20c%29%20%20%2B%20d)
The period is given by
![\frac{\pi}{b}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Cpi%7D%7Bb%7D%20)
If we want the new function to have a period of
![\frac{2}{\pi}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B%5Cpi%7D%20)
Then we solve the following equation for b.
![\frac{\pi}{b} = \frac{2}{\pi}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%5Cpi%7D%7Bb%7D%20%20%3D%20%20%5Cfrac%7B2%7D%7B%5Cpi%7D%20)
![b = \frac{ {\pi}^{2} }{2}](https://tex.z-dn.net/?f=b%20%3D%20%20%5Cfrac%7B%20%7B%5Cpi%7D%5E%7B2%7D%20%7D%7B2%7D%20)
![- \frac{c}{b}](https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7Bc%7D%7Bb%7D%20)
will translate the graph horizontally to the right by
![\frac{c}{b}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bc%7D%7Bb%7D%20)
units.
+d shifts the graph up by d units.
The new function then becomes:
![y = \cot( \frac{ {\pi}^{2} }{2} (x - \frac{\pi}{4} ) )+1](https://tex.z-dn.net/?f=y%20%3D%20%20%5Ccot%28%20%20%5Cfrac%7B%20%7B%5Cpi%7D%5E%7B2%7D%20%7D%7B2%7D%20%20%28x%20%20-%20%20%5Cfrac%7B%5Cpi%7D%7B4%7D%20%29%20%29%2B1)
Bob-Joe-Sam, Sam-Joe-Bob, Bob-Sam-Joe, Sam-Bob-Joe, Joe-Bob-Sam, Joe-Sam-Bob
Hope this helps