Question

Which relation is a function? {(–4, –6), (–3, –2), (1, –2), (1, 0)} {(–2, –12), (–2, 0), (–2, 4), (–2, 11)} {(0,1), (0, 2), (1, 2), (1, 3)} {(8, 1), (4, 1), (0,1), (–15, 1)}

Answer 1

The answer is what the person above me said

Answer 2

Answer:

$\{(8, 1), (4, 1), (0,1), (-15, 1)\}$

Step-by-step explanation:

Given

$\{(-4, -6), (-3, -2), (1, -2), (1, 0)\}$

$\{(-2, -12), (-2, 0), (-2, 4), (-2, 11)\}$

$\{(0,1), (0, 2), (1, 2), (1, 3)\}$

$\{(8, 1), (4, 1), (0,1), (-15, 1)\}$

Required

Determine which is a function

A relation is divided into 2; (x,y)

Where x represents the range and y stands for the domain

For a relation to be a function, the x column must be unique; in other words, there must be only one occurrence of x

Testing each of the given options

A. $\{(-4, -6), (-3, -2), (1, -2), (1, 0)\}$

Start by splitting the relation into x and y columns

$(x,y)$

$(-4, -6)$

$(-3, -2)$

$(1, -2)$

$(1, 0)$

Notice that the third and fourth relation has the same x value of 1;

Hence, this is not a function

B. $\{(-2, -12), (-2, 0), (-2, 4), (-2, 11)\}$

Start by splitting the relation into x and y columns

$(x,y)$

$(-2, -12)$

$(-2, 0)$

$(-2, 4)$

$(-2, 11)$

Notice that all relations has the same x value of -2;

Hence, this is also not a function

C. $\{(0,1), (0, 2), (1, 2), (1, 3)\}$

Start by splitting the relation into x and y columns

$(x,y)$

$(0, 1)$

$(0, 2)$

$(1, 2)$

$(1, 3)$

Notice that the first and second relation has the same x value of 0 and the third and fourth relation has the same x value of 1;

Hence, this is also not a function

D. $\{(8, 1), (4, 1), (0,1), (-15, 1)\}$

Start by splitting the relation into x and y columns

$(x,y)$

$(8, 1)$

$(4, 1)$

$(0, 1)$

$(-15, 1)$

Notice that relation has the unique x values of 8, 4, 0 and -15

Hence, this relation is a function