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gulaghasi [49]
3 years ago
10

"running computer programs and their data are stored in ___"

Computers and Technology
2 answers:
777dan777 [17]3 years ago
6 0

Answer:

The correct answer is: Random Access Memory (RAM).

Explanation:

Random Access Memory or RAM is the physical computer memory that temporarily stores data and functions as the working memory. The more RAM a computer has, the more processes it will be able to handle faster at the same time, improving the overall performance of the system.

Lesechka [4]3 years ago
5 0

Solution:

Running computer programs and their data are stored in Rom.

ROM is "built-in" computer memory containing data that normally can only be read, not written to. ROM contains the programming that allows your computer to be "booted up" or regenerated each time you turn it on. Unlike a computer's random access memory (RAM), the data in ROM is not lost when the computer power is turned off. The ROM is sustained by a small long-life battery in your computer.

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An Organization Chart to support the Appliance Warehouse case study The SWOT Analysis diagram you performed and created to suppo
Ulleksa [173]

<u>Explanation</u>:

Remember, the aim of SWOT Analysis is to perform analysis of a phenomenon or case.

Just as in any analysis it is followed by results and recommendations based on the set rules of the analysis.

<u>The Strengths, Weaknesses, Opportunity identified and Threats can translate to the mission statement </u>of a company. It is important to know that this statement is usually factual and accurate.

3 0
3 years ago
(a) List 5 keys we can type with our left hand fingers
ehidna [41]

Answer:

A) <em><u>a,s,d,f, and either g or caps lock</u></em>

B) <u><em>l,k,j,h, and, ;</em></u>

Explanation:

3 0
3 years ago
Write a function called count_occurrences that takes two strings. The second string should only be one character long. The funct
iVinArrow [24]

Answer:

Here is the Python function:

def count_occurrences (string1 , string2):  # method that takes two strings as parameter and returns how many times second string occurs in first

   count = 0  #counts number of occurrence of string2 in string1

   for word in string1:  #iterates through each word of the string1

       for character in word:  #iterates through each character of each word in string1

           if character == string2:  # checks if the character in string1 is equal to the character of string2

               count = count + 1  #adds 1 to the count of string2 in string1

   return count  #returns number of times the string2 occurs in string1

#in order to check the working of the function add the following lines to the code:    

first_str = input("Enter the first string: ")  #prompts user to enter first string

second_str = input("Enter the second string (one character long): ") #prompts user to enter second string which should be one character long

occurrence = count_occurrences(first_str,second_str)  #calls count_occurrences method by passing both strings to it

print(second_str,"occurs",occurrence,"times in",first_str) #prints how many times the second_str occurs in the first_str on output screen

Explanation:

The program is well explained in the comments added to each statement of the above code. I will explain the program with an example:

Suppose

string1 = "hello world"

string2 = 'l'

So the method count_occurrences() should return how many times l occurs in hello world.

count is used to count the number of occurrences of l in hello world. It is initialized to 0.

The first loop iterates through each word of string1. The first word of string1 is "hello"

The second loop iterates through each character/letter of each word. So the first letter of "hello" word is 'h'.

The if condition if character == string2: checks if the character is equal to string2 i.e. l.

character = "h"

string2 = "l"

The are not equal so the program moves to the next character of word hello which is e. The if condition again evaluates to false because e is not equal to l. So the program moves to the next character of word hello which is l.

This time the if condition evaluates to true because

character = "l"

string2 = "l"

character == string2

l == l

So the if part is executed which has the following statement:

count = count + 1

So the count is added to 1. count was 0 previously. Now

count = 1

Next the program moves to the next character of word hello which is l. This time the if condition evaluates to true because the character l matches with string2. So count is again incremented to 1. count = 2.

Next the program moves to the next character of word hello which is o. The if condition evaluates to false as o does not match with string2 i.e. l. So the count remains 2.

Next the first loop moves to the next word of the string1 = "world". The inner (second) for loop iterates through each character of "world" from "w" to "d" and checks if any character is equal to string2. Only one character is equal to string2 in "world". So count is incremented to 1. Hence count = 3

After the loop ends the statement return count returns the number of times string2 occurs in the string1. So the output is:

l occurs 3 times in hello world  

8 0
3 years ago
The feature that moves text from the right edge of a paragraph to the beginning of the next line as necessary to fit within the
gregori [183]

Answer:

Return Key (Enter Key on Windows)

Explanation:

It is a key on the keyboard that has a downward arrow with corner leftward, it can be used to start a new line of writing.

6 0
2 years ago
are the network administrator for your company. You are installing a new printer in the network. When you check the print server
melamori03 [73]

Answer:

Will have to run the net start spooler command.

Explanation:

  • The printer spooler seems to be accountable for overseeing incoming faxes that have been in effect intended for handling by the printer. Whether this device stops operating, your printer won't publish documentation as well as the machine may not notice it either.
  • To solve these problems, you'll need to run the net start spooler command using the least administrative effort.
5 0
2 years ago
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