Answer:
The elastic extensibility of a piece of string is .08. If the string is 100 cm long, how long will the string be when it is stretched to the point where it becomes plastic? is your ansewer dont take tension
Answer:
<h2><u><em>
Plants use Nitrogen</em></u></h2>
Explanation:
<h3><em>They use it for nutrients</em></h3>
Venus has a surrounding that is approximately one hundred instances thicker than Earth's and has surface temperatures that are extraordinarily hot. Venus no longer has life or water oceans as Earth does.
Venus additionally rotates backward in comparison to Earth and the alternative planets. The geology of Earth is dominated by plate tectonics, Venus has "blob tectonics," wherein the growing of hot material from inside performs a dominant position in sculpting its surface. Venus is also one-of-a-kind from Earth in having miles decrease stage of erosion, because no precipitation and surface wind speeds are very low.
Venus is often called "Earth's dual" because they're similar in size and structure, but Venus has severe floor heat and a dense, poisonous environment. If the sun have been as tall as a typical front door, Earth and Venus could never be about the scale of a nickel.
Learn more about planets here:-brainly.com/question/1286910
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Answer:
<h2>Magnetic field strength in that region is 1.2 T</h2>
Explanation:
As we know by the formula of radius of charge moving in external field is given as

so we will have




now we have

now we have

Answer:
a)1815Joules b) 185Joules
Explanation:
Hooke's law states that the extension of a material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically;
F = ke where;
F is the applied force
k is the elastic constant
e is the extension of the material
From the formula, k = F/e
F1/e1 = F2/e2
If a force of 60N causes an extension of 0.5m of the string from its equilibrium position, the elastic constant of the spring will be ;
k = 60/0.5
k = 120N/m
a) To get the work done in stretching the spring 5.5m from its position,
Work done by the spring = 1/2ke²
Given k = 120N/m, e = 5.5m
Work done = 1/2×120×5.5²
Work done = 60× 5.5²
Work done = 1815Joules
b) work done in compressing the spring 1.5m from its equilibrium position will be gotten using the same formula;
Work done = 1/2ke²
Work done =1/2× 120×1.5²
Works done = 60×1.5²
Work done = 135Joules