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3 years ago

9

Energy in motion is _____ energy. potential scientific kinetic

2 answers:

koban [17]3 years ago

6 0

The correct answer is kinetic energy

Ket [755]3 years ago

4 0

Answer:

kinetic energy

Explanation:

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The chewing muscle, the masseter, is one of the strongest in the human body. It is attached to the mandible (lower jawbone) as s

kifflom [539]

Answer:

Explanation:

Check attachment

6 0

3 years ago

A family is skating at an ice rink. The 58.2 kg mother is holding the

MariettaO [177]

Answer:

When I got this question I had to draw it out so if you have to do that, draw 3 stick figures holding hands, one representing the mother, father, and daughter. Then you write their weights on top of them and then draw an arrow pointing from the father to the mother.

Explanation:

use this formula :

$a_{y}$ = $\frac{Fdadshandy}{msys}$

then you fill it in :

$a_{y}$ = $\frac{100N}{35.5kg+58.2kg}$

$a_{y}$ = $\frac{100N}{93.7kg}$

$a_{y}$ = $1.0672$ $m/s^{2}$

then you multiply that with the daughters weight :

$T_{2} x= m_{2} a_{y}$

$T_{2} x = 35.5kg (1.0672 m/s^{2})$

$T_{2} x = 37.89N$

and that's the answer :) : 37.89N

5 0

3 years ago

Ted Clubber Lang. A hook in boxing primarily involves horizontal flexion of the shoulder while maintaining a constant angle at t

il63 [147K]

Answer:

15 m/s or 1500 cm/s

Explanation:

Given that

Speed of the shoulder, v(h) = 75 cm/s = 0.75 m/s

Distance moved during the hook, d(h) = 5 cm = 0.05 m

Distance moved by the fist, d(f) = 100 cm = 1 m

Average speed of the fist during the hook, v(f) = ? cm/s = m/s

This can be solved by a very simple relation.

d(f) / d(h) = v(f) / v(h)

v(f) = [d(f) * v(h)] / d(h)

v(f) = (1 * 0.75) / 0.05

v(f) = 0.75 / 0.05

v(f) = 15 m/s

Therefore, the average speed of the fist during the hook is 15 m/s or 1500 cm/s

6 0

3 years ago

Tornadoes form in unusually violent thunderstorms when there is sufficient (1) instability and (2) wind shear present in the low

zvonat [6]

its D

i hope this helps to future test takers. i took the test and had to retake it because their wasn't an answer

7 0

3 years ago

Read 2 more answers

A car goes forward along a level road T a constant velocity the additional force needed to being the car into equilibrium is?

eimsori [14]

The additional force needed to bring the car into equilibrium is frictional force.

8 0

2 years ago