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3 years ago

What causes a submarine to rise and descend?

Physics

1 answer:

photoshop1234 [79]3 years ago

6 0

Answer:

When the ballast tanks are filled with air, the submarine rises to the surface because it has positive buoyancy. With water inside the tanks, the sub has negative buoyancy so it sinks deeper into the ocean. The ballast tanks can also be used to help a submarine surface very quickly in an emergency

Explanation:

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An orange is a common fruit that grows on citrus trees. What part of the citrus tree's flower does the orange develop from?

jekas [21]

Citrus × sinensis, orange, orange or sweet orange, is a fruit tree of the genus Citrus, which is part of the family of rutáceas. It is a medium-sized tree -even in optimum growing conditions up to 13 m in height-, perennial, with a large, round or pyramidal crown, with oval leaves between 7 and 10 cm wide and often stipulated and branches sometimes with large spines (more than 10 cm).

Its white flowers, called azahar, are born isolated or in clusters and are extremely fragrant. Its fruit is sweet orange.

Answer:
azahar

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The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103

gavmur [86]

I think the question need to use extrapolation. FInd the linear function of the first and second data. And then, the anwser is 5.4 liters.

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A rock at the edge of a cliff has what kind of energy?

Marina CMI [18]

A rock at the edge of a cliff has potential energy because it isn't in motion, but is located in a place that motion could occur in the near future.

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4 years ago

Ideal gases are often studied at standard ambient temperature and pressure (satp). The international union of pure and applied c

11Alexandr11 [23.1K]

This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.

<h3>Idela gases</h3>

In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.

In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.

Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:

$PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}$

And plug in the numbers we are given:

$\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3$

Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:

$2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}$

Learn more about ideal gases: brainly.com/question/26450101

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3 years ago

A record is spinning at the rate of 25rpm. If a ladybug is sitting 10cm from the center of the record.

marin [14]

A) Angular speed: 0.42 rev/s

B) Frequency: 0.42 Hz

C) Tangential speed: 26.4 cm/s

D) Distance travelled: 528 cm

Explanation:

In this problem, the ladybug is rotating together with the record.

The angular velocity of the ladybug, which is defined as the rate of change of the angular position of the ladybug, in this problem is

$\omega = 25 rpm$

where here it is measured in revolutions per minute.

Keeping in mind that

1 minute = 60 seconds

We can rewrite the angular speed in revolutions per second:

$\omega = 25 \frac{rev}{min} \cdot \frac{1}{60 s/min}=0.42 rev/s$

The relationship between angular speed and frequency of revolution for a rotational motion is given by the equation

$\omega = 2 \pi f$ (1)

where

$\omega$ is the angular speed

f is the frequency of revolution

For the ladybug in this problem,

$\omega=0.42 rev/s$

Keeping in mind that $1 rev = 2\pi rad$ , the angular speed can be rewritten as

$\omega = 0.42 \frac{rev}{s} \cdot 2\pi = 2\pi \cdot 0.42$

And re-arranginf eq.(1), we can find the frequency:

$f=\frac{\omega}{2\pi}=\frac{(2\pi)0.42}{2\pi}=0.42 Hz$

And the frequency is the number of complete revolutions made per second.

For an object in circular motion, the tangential speed is related to the angular speed by the equation

$v=\omega r$

where

$\omega$ is the angular speed

v is the tangential speed

r is the distance of the object from the axis of rotation

For the ladybug here,

$\omega = 2\pi \cdot 0.42 rad/s$ is the angular speed

r = 10 cm = 0.10 m is the distance from the center of the record

So, its tangential speed is

$v=(2\pi \cdot 0.42)(0.10)=0.264 m/s = 26.4 cm/s$

The tangential speed of the ladybug in this motion is constant (because the angular speed is also constant), so we can find the distance travelled using the equation for uniform motion:

$d=vt$