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brilliants [131]
3 years ago
12

A d'Arsonal meter with an internal resistance of 1 kohm requires 10 mA to produce full-scale deflection. Calculate thew value of

a series
Physics
1 answer:
creativ13 [48]3 years ago
4 0
<h2>Question:</h2>

A d’Arsonval meter with an internal resistance of 1 kΩ requires 10 mA to produce full-scale deflection. Calculate the value of a series resistance needed to measure 50 V of full scale.

<h2>Answer:</h2>

4kΩ

<h2>Explanation:</h2>

Given;

internal resistance, r = 1kΩ

current, I = 10mA = 0.01A

Voltage of full scale, V = 50V

Since there is full scale voltage of 50V, then the combined or total resistance (R) of the circuit is given as follows;

From Ohm's law

V = IR

R = \frac{V}{I}                 [substitute the values of V and I]

R = \frac{50}{0.01}

R = 5000Ω = 5kΩ

The combined resistance (R) is actually the total resistance of the series arrangement of the series resistance(R_{S}) and the internal resistance (r) in the circuit. i.e

R = R_{S} + r

R_{S} = R - r                 [Substitute the values of R and r]

R_{S} = 5kΩ - 1kΩ

R_{S} = 4kΩ

Therefore the series resistance is 4kΩ

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But that's cheap, and hardly worth even 5 points.
If we want to talk energy, let's use the actual scientific unit of energy.
________________________________________________

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