Let s be Seth's age. let r be Romans age. 5 years ago Seth was s-5 and Roman was three times as old, or 3(s-5), or 3s-15=r-5
in ten years Seth will be s+10 and Roman will be twice as old, or 2(s+10), or 2s+20=r+10
3s-15 =r-5
r=3s-10
2s+20=r+10
r=2s+10
3s-10=2s+10
s=20
Seth is 20 years old
setting the two equations equal gives us
3(s-5)=2(s+10)
3s-15=2s+20
s=35
I believe the answer is 4/15.
7/8 = y/11
so multiply 11 to both sides of the equation
so now its (7*11)/8= y
y=77/8
if decimal then 9.625
hope that helps
Answer:
-12u + 11z
Step-by-step explanation:
The above expression cannot be simplified, for:
1) There is no common variable (one being <em>u</em>, and the other being <em>z</em>).
2) There are no common factors in between 12 & 11)
- Factors of 12: 1, 2, 3, 4, 6, 12
- Factors of 11: 1, 11
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