Factorize 6x^2+17x+5 by splitting middle term and by using the factor theorem

Apply the junction rule to the junction labeled with the number 1 (at the bottom of the resistor of resistance R2R2R_2). Answer

Ira Lisetskai [31]

Answer:

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Step-by-step explanation:

The image of the circuit is obtained online and attached to the question.

The junction rule is essentially a law of conservation of current (charges). It applies to electrical circuits at steady state.

It explains that the for any given junction (node in an electrical circuit), the sum of current entering the junction is equal to the sum of current leaving the junction. That is, the net sum of current at any junction is zero.

Current entering a junction is assigned a positive sign and that leaving the junction is assigned a negative sign.

Σ I = 0

From the image of the circuit attached, I₁ is leaving the junction labelled number 1 and I₂ and I₃ are entering the junction.

Hence,

-I₁ + I₂ + I₃ = 0

I₁ = I₂ + I₃

Hope this Helps!!!

5 0

3 years ago

Choose the domain for which each function is defined

klemol [59]

Answer:

Part 1) $f(x)=\frac{x+4}{x}$ -----> $x\neq 0$

Part 2) $f(x)=\frac{x}{x+4}$ ----> $x\neq -4$

Part 3) $f(x)=x(x+4)$ ----> All real numbers

Part 4) $f(x)=\frac{4}{x^2+8x+16}$ ----> $x\neq -4$

Step-by-step explanation:

we know that

The domain of a function is the set of all possible values of x

Part 1) we have

$f(x)=\frac{x+4}{x}$

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=0 the function is not defined

therefore

The domain is

$x\neq 0$

Part 2) we have

$f(x)=\frac{x}{x+4}$

we know that

In a quotient the denominator cannot be equal to zero

so

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

Part 3) we have

$f(x)=x(x+4)$

Applying the distributive property

$f*(x)=x^2+4x$

This is a vertical parabola open upward

The function is defined by all the values of x

therefore

The domain is all real numbers

Part 4) we have

$f(x)=\frac{4}{x^2+8x+16}$

we know that

In a quotient the denominator cannot be equal to zero

so

Equate the denominator to zero

$x^2+8x+16=0$

Remember that

$x^2+8x+16=(x+4)^2$

( $x+4)^2=0$

The solution is x=-4

so

For the value of x=-4 the function is not defined

therefore

The domain is

$x\neq -4$

6 0

3 years ago

Which of the following is an example of a sample that would NOT be random?

Sloan [31]

Answer: D

"Separating the students on the list into boys and girls and choosing a sample from each group that is proportional to the size of the group."

Step-by-step explanation:

You are sampling an equal amount of boys and girls since your getting an equal sample of each gender. (Not random)

5 0

3 years ago

Write an equation perpendicular to x-4y=20 that passes through the point 2,-5

marshall27 [118]

Answer:

4x +y = 3

Step-by-step explanation:

Perpendicular lines have slopes that are the negative reciprocals of one another. When the equation of the line is written in standard form like this, the equation of the perpendicular line can be written by swapping the x- and y-coefficients and negating one of them. Doing this much would give you ...

4x +y = (constant)

Note that we have chosen to make the equation read 4x+y, not -4x-y. The reason is that "standard form" requires the leading coefficient to be positive.

Now, you just need to make sure the constant is appropriate for the point you want the line to go through. So, it needs to be ...

4(2) +(-5) = constant = 3

The line of interest has equation ...

4x + y = 3

3 0

3 years ago

What is the slope intercept form of the equation of the line

Vlad [161]

The answer is C, your b in the equation is 4, and your slope is 1/2. Starting from four, you move up one and right two which means the slope is 1/2.

6 0

3 years ago