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Angelina_Jolie [31]
2 years ago
7

Maria's book is longer than Brandon's. The difference in the two book lengths is 56

Mathematics
1 answer:
Bingel [31]2 years ago
7 0

Answer:

Maria's book is 202 pages long, Brandon's book is 146 pages long

Step-by-step explanation:

We can set this up with 2 variables: lets say that Maria's book length is x and Brandon's is y.

We can see that Maria's book is 56 pages longer than Brandon's and can come up with an equation:

x=y+56

We also see that their booklengths add up to 348, and can get:

x+y=348

From here, we solve for x and y. We can use substitution to find y.

x+y=348

(y+56)+y=348

2y=292

y=146

Here we plug in for x:

x=y+56

x=(146)+56

x=202

Therefor we get that Maria's book is 202 pages long, Brandon's book is 146 pages long

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<h2>(a)</h2>

Case 1: both balls are white.

At the beginning we have b+w balls. We want to pick a white one, so we have a probability of \frac{w}{b+w} of picking a white one.

If this happens, we're left with w-1 white balls and still b black balls, for a total of b+w-1 balls. So, now, the probability of picking a white ball is

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The probability of the two events happening one after the other is the product of the probabilities, so you pick two whites with probability

\dfrac{w}{b+w}\cdot \dfrac{w-1}{b+w-1}=\dfrac{w(w-1)}{(b+w)(b+w-1)}

Case 2: both balls are black

The exact same logic leads to a probability of

\dfrac{b}{b+w}\cdot \dfrac{b-1}{b+w-1}=\dfrac{b(b-1)}{(b+w)(b+w-1)}

These two events are mutually exclusive (we either pick two whites or two blacks!), so the total probability of picking two balls of the same colour is

\dfrac{w(w-1)}{(b+w)(b+w-1)}+\dfrac{b(b-1)}{(b+w)(b+w-1)}=\dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

<h2>(b)</h2>

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This leads to an overall probability of

\left(\dfrac{w}{b+w}\right)^2+\left(\dfrac{b}{b+w}\right)^2 = \dfrac{w^2+b^2}{(b+w)^2}

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<h2>(c)</h2>

We want to prove that

\dfrac{w^2+b^2}{(b+w)^2}\geq \dfrac{w(w-1)+b(b-1)}{(b+w)(b+w-1)}

Expading all squares and products, this translates to

\dfrac{w^2+b^2}{b^2+2bw+w^2}\geq \dfrac{w^2+b^2-b-w}{b^2+2bw+w^2-b-w}

As you can see, this inequality comes in the form

\dfrac{x}{y}\geq \dfrac{x-k}{y-k}

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And this is our case, because in our case we have

  1. x=b^2+w^2
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FV=PV[1+\frac{r}{100}]^{n}

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It is provided that $5,000 were deposited now and $3,000 deposited after 6 years at 10% compound interest. The amount of time the money is invested for is 14 years.

The expression to compute the amount in the investment account after 14 years is,

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Thus, the expression to compute the amount in the investment account after 14 years is: <em>FV</em> = [5000 ×(1.10)¹⁴] + [3000 ×(1.10)⁸].

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Answer: B 15 units

Step-by-step explanation:

3 0
3 years ago
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