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vagabundo [1.1K]
3 years ago
13

A research company wants to test the claim that a new multivitamin helps to improve short term memory. State the objective of th

e experiment, suggest a population, determine the experimental and control groups, and describe a sample procedure.
(SHOW WORK)​
Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
4 0

Answer:

I would think that you would want to have the multivitamin and then a placebo, then conduct an experiment testing the results of the multivitamin and observe the effects on both groups taking the medicine.

Step-by-step explanation:

your control group would be the placebo and your experimental group would be the multivitamin...

GaryK [48]3 years ago
4 0

Answer with explanation:

Objective of the experiment:

       The Multivitamin made by research company is beneficial or not for abolishing short term memory.  

Population

The population can be chosen from the largest city hospital where people are suffering from short term memory loss.

Suppose 100 people are suffering from short term memory loss.

Experimental and control group

  Suppose 40 people are being tested that is in experimental group and 60 people are in Control group.

Sample Procedure

After selecting 40 people in the experimental group , and then providing them Multivitamin for few days ,and then checking whether it is helping them to attain their memory or not is the procedure.

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Answer:

a) p(X= 2) = 0.261

b) P(x>2) = 0.566

c) P(2<x<5)  = 0.334

Step-by-step explanation:

Given 24% of U.S. adults say they are more likely to make purchases during a sales tax holiday

Probability 0f U.S. adults say they are more likely to make purchases during a sales tax holiday (p) = 0.24

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By using Poisson distribution

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λ = np = 10 X 0.24 = 2.4

a)

The probability of getting exactly '2'

The probability p(X= 2) = e^{-\alpha } \frac{\alpha^r }{r! }

p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }

p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }= 0.261

b) The probability of getting more than '2'

P(X>2) = 1- {p(x=0)+p(x=1)+p(x=2)}

                = e^{-2.4 } \frac{(2.4)\^0 }{0! }+ e^{-2.4 } \frac{(2.4)\^1 }{1!}+e^{-2.4 } \frac{(2.4)\^2 }{2!}

              = 0.090 + 0.2177+0.261 = 0.566

P(x>2) = 0.566

c) The probability of getting between  two and five

P( 2<x<5) = P(x=3)+p(x=4) == e^{-2.4 } \frac{(2.4)\^3 }{3! }+ e^{-2.4 } \frac{(2.4)\^4 }{4!}+

P(2<x<5) = 0.2090 + 0.125 = 0.334

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bogdanovich [222]

Answer:

Third table

Step-by-step explanation:

For the relationship to be proportional

y/x = constant

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Step-by-step explanation:

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4 0
2 years ago
<img src="https://tex.z-dn.net/?f=f%20%2B%20523.89%20%20%3D%20812.57" id="TexFormula1" title="f + 523.89 = 812.57" alt="f + 523
Evgesh-ka [11]

Answer:

D.f=288.68

Step-by-step explanation:

f+ 523.89 = 812.57

subtract 523.89 from both sides

f+ 523.89-523.89 = 812.57-523.89

f = 288.68

8 0
3 years ago
Read 2 more answers
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