Question

Pls can someone help meB2%7D%20-%20%20log10%20%5Csqrt%7B7%7D%20" id="TexFormula1" title=" log10 \sqrt{36} + log10 \sqrt{2} - log10 \sqrt{7} " alt=" log10 \sqrt{36} + log10 \sqrt{2} - log10 \sqrt{7} " align="absmiddle" class="latex-formula">
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Answer 1

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7}$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$