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3 years ago

14

Pls can someone help me

B2%7D%20-%20%20log10%20%5Csqrt%7B7%7D%20" id="TexFormula1" title=" log10 \sqrt{36} + log10 \sqrt{2} - log10 \sqrt{7} " alt=" log10 \sqrt{36} + log10 \sqrt{2} - log10 \sqrt{7} " align="absmiddle" class="latex-formula">

1 answer:

Firlakuza [10]3 years ago

6 0

Answer:

$= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

Step-by-step explanation:

Given the expression $log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\$

According to the law of logarithm;

loga + log b = log(ab) and log a - log b = log(a/b)

The given expression becomes;

$log10\sqrt{36} + log10\sqrt{2} - log10\sqrt{7} \\= log_{10}(\frac{\sqrt{36} \times \sqrt{2} }{\sqrt{7} })\\= log_{10}(\frac{6\sqrt{2} }{\sqrt{7} } )$

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zvonat [6]

Given:

Triangle LJK.

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To find:

The length of missing side JK.

Solution:

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Using law of cosine:

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Substitute the given values.

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3 years ago

A thermometer reading 7 °C is brought into a room with a constant temperature of 34°C. If the thermometer reads 14 °C after 4 m

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x: time in minutes
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Step-by-step explanation:

1.

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We have:

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AB = 1 + x

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