1.5 pages her friend can read so the formula would be

1.5x and x being the number of pages her friend reads

1.5 times 20 is not 25 it's 30

therefore no Aileen's mom is not correct

3 0

3 years ago

Read 2 more answers

A ball is tossed between three friends. The first toss is 8.6 feet, the second is 5.8 feet, and the third toss is 7.5 feet, whic

Rainbow [258]

angles formed by these tosses are $79.45, 59.02$ and $41.53$ degrees to the nearest hundredth.

<u>Step-by-step explanation:</u>

Here , We have a triangle with sides of length 8.6 feet, 5.8 feet and 7.5 feet.

The Law of Cosines (also called the Cosine Rule) says:

$c^2 = a^2 + b^2 - 2ab (cosx)$

Using the Cosine Rule to find the measure of the angle opposite the side of length 8.6 feet:

⇒ $c^2 = a^2 + b^2 - 2ab (cosx)$

⇒ $c^2 -a^2 - b^2 = -2ab (cosx)$

⇒ $(cosx) =\frac{ c^2 -a^2 - b^2}{ -2ab}$

⇒ $(cosx) =\frac{(8.6^2 - 5.8^2 - 7.5^2)}{ ( -2(5.8)7.5)}$

⇒ $(cosx) =0.18310$

⇒ $cos^{-1}(cosx) = cos^{-1}(0.18310)$

⇒ $x = 79.45$

The Law of Sines (or Sine Rule) is very useful for solving triangles:

$\frac{a}{sin A} = \frac{ b}{sin B} = \frac{c}{sin C}$

We can now find another angle using the sine rule:

⇒ $\frac{ 8.6 }{ sin 79.45} = \frac{7.5}{ sin Y}$

⇒ $sin Y = \frac{(7.5 (sin 79.45))}{ 8.6}$

⇒ $Y = 59.02 degrees$

So, the third angle = $180 - 79.45 - 59.02 = 41.53 degrees.$

Therefore, angles formed by these tosses are $79.45, 59.02$ and $41.53$ degrees to the nearest hundredth.

4 0

3 years ago

Mr. Peter's has 80 sheets of colored paper. Seven of his students need the paper for a project. How many sheets does each studen

Julli [10]

Answer:

Each student gets 11 pieces.

Step-by-step explanation:

80 ÷ 7 = 11.42857

80 divided by 7 comes out to a decimal therefore, you will have a remainder. 7 × 11 = 77

The answer would be 11 remainder 3.

8 0

3 years ago

(x^4)^3=(x^3)^4 true or false

telo118 [61]

Step-by-step explanation:

(x^4)^3=(x^3)^4 , true

=> x^(4×3) = x^(3×4) = x^12

13^4 x 13^7= (13^4)^7, false

13^(4+7) = 13^11

(13^4)^7 = 13^(4×7) = 13^28

y^5 x y^0/y^3=(y^2)^1 , true

y^5 x y^0/y^3 = y^(5+0-3) = y^2

(y^2)^1 = y^(2×1) = y^2

q^0 x q^5/q^2=(q^3)^2/q^3, true

q^0 x q^5/q^2= q^(0+5-2)= q^3

(q^3)^2/q^3 = q^(3×2-3) = q^3

6 0

2 years ago

Read 2 more answers