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dmitriy555 [2]
2 years ago
12

The price to rent a bike for t hours is shown in the table.

Mathematics
1 answer:
Degger [83]2 years ago
6 0
7t = c

for every hour you ride your bike, it is seven dollars. for example, 1 hour = $7 or 2 hours =$14
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What is the perimeter of a triangle with vertices of (5,1) (-3,3) (-7,-3)
timurjin [86]
Vertices:\\
A(5,1)\\B(-3,3)\\C(-7,-3)\\\\ You\ must\ find\ length\ of\ AB,\ BC,\ AC.\\\\
A(5,1)\ \ \ \ \ \ B(-3,3)\\\\Distance\ between\ A \ and\ B:\\AB=\sqrt{(x_B-x_A)^2+(y_A-y_B)^2}\\\\AB=\sqrt{(-3-5)^2+(3-1)^2}\\AB=\sqrt{8^2+2^2}\\AB=\sqrt{64+4}\\AB=\sqrt{68}

 B(-3,3)\ \ \ \ C(-7,-3)\\\\Distance\ between\ B \ and\ C:\\BC=\sqrt{(x_C-x_B)^2+(y_C-y_B)^2}\\\\BC=\sqrt{(-7-(-3))^2+(-3-3)^2}\\BC=\sqrt{(-4)^2+(-6)^2}\\BC=\sqrt{16+36}\\BC=\sqrt{52}A(5,1)\ \ \ \ \ \ C(-7,-3)\\\\Distance\ between\ A \ and\ C:\\AC=\sqrt{(x_C-x_A)^2+(y_C-y_A)^2}\\\\AC=\sqrt{(-7-5)^2+(-3-1)^2}\\AC=\sqrt{(-12)^2+(-4)^2}\\AC=\sqrt{144+16}\\AC=\sqrt{160}Perimeter\ of\ triangle=\ AB+AC+BC=\\\sqrt{68}+\sqrt{52}+\sqrt{160}=2\sqrt{17}+2\sqrt{13}+2\sqrt{40}
5 0
2 years ago
What is the value of x in the equation , when y = 3?<br><br> x = 6<br> x = 7<br> x = 8<br> x = 9
Misha Larkins [42]

Answer:

6, 7, 8, 9 respectively

Step-by-step explanation:

The variable y doesn't matter here because it is not in the equation at all.

5 0
3 years ago
Read 2 more answers
ms. reynolds, the math teacher, was disappointed to announce that only 22% of her 68 students passed an exam. How many students
Ratling [72]
Either a student passes an exam or fails it. that means the percentage of students who pass plus the percentage of students who fail must add to 100%. this also means that if 22% pass, then 78% fail. there are 68 students total and 78% fail so the number of students failing is:
(78/100)(68) = 53.04 which is approximately 53 students.

let me know if you have any questions!!!!
3 0
3 years ago
Step by step explanation
SSSSS [86.1K]

Answer:

only a is the right triangle

Step-by-step explanation:

only a is the right triangle because it satisfies the pythagorean theorem.

a.)

c ^{2}  = a ^{2}  + b ^{2}  \\ 63 = 25 + 38\\ 63 = 63 \\ true

while b,

b.)

c ^{2}  = a ^{2}  + b ^{2}  \\ 60 = 25 + 38 \\ 60 = 63 \\ false

8 0
2 years ago
joe weighs 20lbs.less yhantwice jeffs weight.if jeff would gain 10lbs.,then together they wouldweigh 250lbs. how much does each
masya89 [10]
So,

Let x represent Joe's weight and y represent Jeff's weight.

"Joe weighs 20 lbs. less than twice Jeff's weight."
x = 2y - 20

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
(y + 10) + x = 250

We now have our two open sentences.
x = 2y - 20
(y + 10) + x = 250

Get rid of parentheses.
x = 2y - 20
x + y + 10 = 250

We will use Elimination by Substitution.
2y - 20 + y + 10 = 250

Collect Like Terms.
3y - 10 = 250

Add 10 to both sides.
3y = 260

Divide both sides by 3.
Jeff's\ weight = 86 \frac{2}{3} \ lbs.

Substitute again.
x = 2(86 \frac{2}{3} )-20

Multiply.
x = 173 \frac{1}{3} -20

Subtract.
Joe's\ weight = 153 \frac{1}{3}\ lbs.

Check.

"Joe weighs 20 lbs. less than twice Jeff's weight."
Jeff's weight times two is 173 and one-third.
20 lbs. less than that is 153 and one-third lbs. Check.

"If Jeff would gain 10 lbs., then together they would weigh 250 lbs."
86 and two-thirds + 10 = 96 and two-thirds.
96 and two-thirds + 153 and one-third equals 250 lbs. Check.

Joe's\ weight\ is\ 153 \frac{1}{3} \ lbs.
Jeff's\ weight\ is\ 86 \frac{2}{3} \ lbs.
3 0
3 years ago
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