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muminat
3 years ago
7

A square is a rhombus Never Always Sometimes

Mathematics
1 answer:
stira [4]3 years ago
7 0
Always!


Always!


Always!
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Passes through (3,-6) and (-1,2) slope intercept form?
IRISSAK [1]

Answer:

2/1

Step-by-step explanation:

8/4 which is also 2/1

7 0
2 years ago
1. A test-tube has a diameter of 3cm. How many turns would a piece of thread of length
Alex Ar [27]

So if we think of a test tube, it looks sort of like a cylinder. This means that its cross-section would be a circle. To find out how many turns a piece of thread would make around the test tube, we need to find the circumference of the test tube, then divide the length of the string by the circumference.

Step 1) Find the circumference

C = pi x diameter

C = 3.14 x 3

C = 9.42

Step 2) Divide the length of the string by the circumference

90.42 / 9.42 = 9.5987

The string would make approximately 9.60 turns around the test tube.

Hope this helps!! :)

6 0
2 years ago
Someone please help asap
joja [24]
Solve the equation of the function for n.

a(n) = 3n - 20

a = 3n - 20

a + 20 = 3n

(a + 20)/3 = n

n = (a + 20)/3

n(a) = (a + 20)/3
6 0
2 years ago
9. I NEED HELP ASAP!! PLEASE PUT AND ANSWER AND STEP BY STEP EQUATION!! IF YOU DON'T KNOW THE ANSWER DON'T PUT ANYTHING!!
stiv31 [10]
9.) Answer: B. f(x) = 4 - x



Explanation/Proof:

If we substitute, the answers are correct.

f(x) = 4 - (1)

f(x) = 3 ✅


f(x) = 4 - (2)

f(x) = 2 ✅


And so on and so forth.

3 0
2 years ago
Read 2 more answers
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Aleks [24]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

6 0
3 years ago
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