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3 years ago

Find the side AB using the law of sines with the one of the sides 11 and the angles 82 and 44 degrees

Mathematics

2 answers:

Rasek [7]3 years ago

5 0

Answer:

7.7

Step-by-step explanation: We are trying to find side c or side AB

Using the law of sines formula,

a/sin a= b/sin b c/sin c we can solve for missing side.

We are given side BC or side a which is 11

We also are given angle A is 82 degrees

Angle C is 44 degrees also.

So let set up a proportion.

11/sin 82= x/sin 44

11/sin 82× sin 44=x

x= 7.7

Alex17521 [72]3 years ago

4 0

7.7, is answer have a great dayyyyy :)))) mwah

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scoundrel [369]

Your answer is not correct.

The correct answer is the third one:

-No, because the distance from the origin to point (7,-7) is greater than the radius of the circle.

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3 years ago

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den301095 [7]

Answer:

Step-by-step explanation:

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3 years ago

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

See attachment for result of 1-VarStats

8 0

3 years ago

Let f(x) = (5)^x+1 .Evaluate f (-3) without using a calculator

rewona [7]

Answer:

$f\left(-3\right)=\frac{126}{125}$

Step-by-step explanation:

Given

$f\left(x\right)\:=\:\left(5\right)^x+1$

Putting x = -3 to find f(-3)

$f\left(-3\right)\:=\:\left(5\right)^{\left(-3\right)}+1$

$5^{-3}=\frac{1}{125}$ ∵ $\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$f\left(-3\right)=\frac{1}{125}+1$

$\mathrm{Convert\:element\:to\:fraction}:\quad \:1=\frac{1\cdot \:125}{125}$

$f\left(-3\right)=\frac{1\cdot \:\:125}{125}+\frac{1}{125}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$f\left(-3\right)=\frac{1\cdot \:\:125+1}{125}$

$f\left(-3\right)=\frac{126}{125}$ ∵ $1\cdot \:125+1=126$

Thus,

$f\left(-3\right)=\frac{126}{125}$

6 0

4 years ago

75 days is how many months?

Natali [406]

Well 2 months and 16 days

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3 years ago