Answer:
(-4, -1/2)
Step-by-step explanation:
to calculate the midpoints bt of the line use the ormula:

Where (x1, x2) is one coordinate point and (y1, y2) is anither coordinate point. Any two points will work, but I chose A (-5,-4) and B (-3, 3).

(-4, -1/2)
Answer:
150 ft
Step-by-step explanation:
triangle area formula= (b*h)/2
25 time 12 is 300. divide 300 by 2 and get 150.
Answer:
A) y = (x + 3)² + 4
B) y = (x - 3)² + 2
C) y = (x - 1)² - 5
Step-by-step explanation:
2 units UP means that the vertex will be shifted from (-3 , 2) to (-3, (2 + 2) or (-3, 4)
As the y = (x + 3)² will still be zero at x = -3, we just need to change the "+ 2" to
"+ 4" to shift the curve upward by 2
y = (x + 3)² + 4
When we want to shift the curve to the right, we want the vertex to move from (-3, 2) to (3, 2)
This means that the term in parenthesis must be zero with our desired x value
(3 + C)² = 0
3 + C = 0
C = -3
y = (x - 3)² + 2
4 units right and 7 units down mean that the vertex is desired at (1, -5)
(1 + C)² = 0
C = -1
y = (x - 1)² - 5
Answer:
D
Step-by-step explanation:
Add 7 and 3 which is 10
3^10 is 59049 which is the same as 3^7*3*3
A second degree polynomial function has the general form:

, where

.
The leading coefficient is a, so we have a=-1.
5 is a double root means that :
i) f(5)=0,
ii) the discriminant D is 0, where

.
Substituting x=5, we have
f(5)=a(5)^2+b(5)+c,
and since f(5)=0, and a is -1 we have:
0=-25+5b+c
thus c=25-5b.
By ii)

.
Substituting a with -1 and c with 25-5b we have:
Finally we find c: c=25-5b=25-50=-25
Thus the function is

Remark: It is also possible to solve the problem by considering the form

directly.
In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is