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blondinia [14]
4 years ago
12

4x + 5a + 4y + 5b4x+5a+4y+5b4, x, plus, 5, a, plus, 4, y, plus, 5, b

Mathematics
1 answer:
prohojiy [21]4 years ago
5 0
This was very hard but I guess your answer would be 4x+10a+8y+20bx+5b^4+4+5,a,4,y,15,b
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I need immediate help, ignore the bottom part.
kipiarov [429]

Answer:

100

Step-by-step explanation:

Idk I'm not smart enough for this

Puurrr

4 0
3 years ago
Does anyone know about this
Dafna11 [192]

Answer:

11.0

Step-by-step explanation:

Using Pythagoras' identity in the lower right triangle.

let the hypotenuse be x , then

x² = 4² + 9² = 16 + 81 = 97

Within the rectangle, use Pythagoras' identity in the lower right triangle.

let y be the dotted line , then

y² = x² + 5² = 97 + 25 = 122 ( take the square root of both sides )

y = \sqrt{122} ≈ 11.0 ( to the nearest tenth )

The dotted line is approximately 11.0 units

6 0
3 years ago
What does (-7)^2 eaqual??
adell [148]
(-7)^2 = (-7)(-7) = 49

So, 49 is the answer.
3 0
3 years ago
I need Help on this one guys
kotykmax [81]
48-12*2=x tsp
solve for x using order of operations

12*2=24
48-24=24
24 tsp of vanilla remains.

8 0
3 years ago
Determine the domain of (f/g)(x) when f (x)=1/x and g (x)=sqrtx+5
mash [69]

we are given

f(x)=\frac{1}{x}

g(x)=\sqrt{x+5}

Calculation of (f/g)(x):

(\frac{f}{g})(x)=\frac{f(x)}{g(x)}

now, we can plug values

(\frac{f}{g})(x)=\frac{\frac{1}{x}}{\sqrt{x+5}}

now, we can simplify it

(\frac{f}{g})(x)=\frac{1}{x\sqrt{x+5}}

Domain:

we know that domain is all possible values of x for which any function is defined

function will be undefined when denominator =0

x\sqrt{x+5} =0

x=-5,x=0

we are given sqrt function

and we know that value inside sqrt will always be greater than 0

x+5>0

x>-5

so, domain will be

(-5,0)U(0,\infty)..............Answer

5 0
4 years ago
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