A. C. D. E. F.
These all have variability.
If the discriminant b^2-4ac is 0, then you have TWO EQUAL, REAL ROOTS.
If you're given the x-intercepts, you can determine the factors of the polynomial as follows: Take -3, change the sign and write (x+3). Take 5, change the sign and write (x-5). Then the eq'n of the parabola is
f(x) = (x+3)(x-5) = x^2 - 2x -15, in which a=1, b = -2 and c= -15.
You can find the x-coordinate of the vertex, which is also the equation of the axis of symmetry, using
x= -b / (2a). Here, x = -(-2) / (2[1]), or x = 1
Find the y-coordinate by subbing 1 for x in the equation above:
y = (1)^2 - 2(1) - 15 = 1 - 2 - 15 = -16
The vertex is at (1, -16) and the equation of the axis of symm. is x = 1.
Answer:
x = 6, y =3
Step-by-step explanation:
4x-7y=3
x-7y=-15
Multiply the first equation by -1
-4x+7y=-3
Then add this to the second equation to eliminate y
-4x+7y=-3
x-7y=-15
------------------
-3x +0y = -18
-3x = -18
Divide by -3
-3x/-3 = -18/-3
x = 6
Now find y
x -7y = -15
6 -7y = -15
Subtract 6 from each side
6-7y-6 = -15-6
-7y = -21
Divide by -7
-7y/-7 = -21/-7
y =3
