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padilas [110]
3 years ago
6

Also how would you round 2.59 to the nearest tenths ?

Mathematics
2 answers:
Strike441 [17]3 years ago
6 0

Answer:

2.6

Step-by-step explanation:

When rounding, if the decimal place after what you are rounding is ≥5, you round up. ≤4, you dont do anything.

Example:

6.37 rounded to the nearest tenth is 6.4 because the 7 in the hundredths place is ≥5

5.32 rounded to the nearest  tenth is 5.3 because 2 is ≤5 so we do nothing.

In our problem:

2.59 rounded to the nearest 10th is 2.6 because 9 is ≥5 so we round up.

Maslowich3 years ago
5 0

Answer:

<em>2.6</em>

Step-by-step explanation:

The tenths digit is the 5.

Drop every digit after the 5. You get 2.5

Now you need to see if the 5 stays as it is or if it goes up by 1 to 6.

The first digit after the 5 you dropped is 9. Since 9 is greater than 4, the previous digit goes up by 1, so the 5 becomes a 6.

The final answer is 2.6

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JWISOSOOS someone help me n show me how to do it 2. Thanks goodnight:&gt;&gt;
posledela

Answer:

2/3(3x+9)=-2(2x+6)

2/3(3x+2x)=-2(9+6)

2/3×5x=-2+15

10x/3=13

3x=13

x=13-3

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4 0
2 years ago
What is equivalent to 31/50 in fraction form
tigry1 [53]
\frac{31}{50} = \frac{31}{50} \times \frac{2}{2} =\boxed{\bf{ \frac{62}{100} }}

62/100 is equivalent to 31/50.
6 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
2 years ago
A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 140 lb and each bo
Sindrei [870]

Answer:He can bring up 13.8333333333 boxes each trip

Step-by-step explanation:

970-140= 830

830÷60=13.8333333333

5 0
3 years ago
What is the value of the expression below when y = 3?<br> 10y - 8
ycow [4]

Answer:

<h2>22</h2>

Step-by-step explanation:

<h3>Given, y = 3 </h3>

substitute this value in given expression

<em>=> 10y - 8</em>

<em>=</em><em>></em><em> </em><em>1</em><em>0</em><em>(</em><em>3</em><em>)</em><em> </em><em>-</em><em> </em><em>8</em><em> </em>

<em>=</em><em>></em><em> </em><em>3</em><em>0</em><em> </em><em>-</em><em> </em><em>8</em><em> </em>

<em>=</em><em>></em><em> </em><em>2</em><em>2</em><em>.</em><em>.</em><em>.</em><em>ans</em>

<h2>HOPE IT HELPS U!!!!</h2>
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2 years ago
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