A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.
C) The probability the golfer got six holes-in-one during a single game is close to 0%.
<h2 /><h2><u>How to determine probabilities</u></h2>
Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:
- 1 - 0.12 = 0.88
- 0.88 ^ 17 = 0.1138
- 0.88 ^ 18 = 0.1001
Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
- 0.88 ^ 18 - 0.12 ^ 2 = X
- 0.0857 = X
Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.
- 0.12 ^ 6 x 0.88 ^ 12 = X
- 0.0000000001 = X
Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.
Learn more about probabilities in brainly.com/question/25273534
Mrs. Annie went to a store, spent half of her money and then $10 more. She went to a second store, spent half of her remaining money and then $10 more. But she then had no money left. How much money did she have to begin with when she went to the first store?
Answer: $60
Answer:
The tamaraw or Mindoro dwarf buffalo (Bubalus mindorensis) is a small hoofed mammal belonging to the family Bovidae. It is endemic to the island of Mindoro in the Philippines, and is the only endemic Philippine bovine.
Answer:
Exact form: 37/8 Decimal form: 4.625 Mixed number form: 4 5/8
Step-by-step explanation:
dd the whole numbers first.
4+\frac{1}{4}+\frac{3}{8}
4+
4
1
+
8
3
2 Find the Least Common Denominator (LCD) of \frac{1}{4},\frac{3}{8}
4
1
,
8
3
. In other words, find the Least Common Multiple (LCM) of 4,84,8.
LCD = 88
3 Make the denominators the same as the LCD.
4+\frac{1\times 2}{4\times 2}+\frac{3}{8}
4+
4×2
1×2
+
8
3
4 Simplify. Denominators are now the same.
4+\frac{2}{8}+\frac{3}{8}
4+
8
2
+
8
3
5 Join the denominators.
4+\frac{2+3}{8}
4+
8
2+3
6 Simplify.
4\frac{5}{8}
4
8
5
