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2 years ago

the regular price of pants is $38.00 the pants are discounted 35% how much do the pants cost after the discount is applied

Mathematics

2 answers:

Vitek1552 [10]2 years ago

6 0

Answer:

$24.70

Step-by-step explanation:

38.00 - 13.30 = 24.70

andreyandreev [35.5K]2 years ago

4 0

38.00 * .35 = 13.30

38.00- 13.30= $24.70

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4232 divided by 18 also estimate

igomit [66]

4232 divided by 18 equals 235.1

6 0

2 years ago

The length of an object in feet is equal to three times its length in yards. The length of a water slide is 48 feet. Write and s

wariber [46]

Yards=x
ft=3x
48=3x
x=16
the length if the water slide in yards is 3. 3 yards

5 0

2 years ago

Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account

Diano4ka-milaya [45]

Answer:

$\$180.55$

Step-by-step explanation:

step 1

Simple interest

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04$

substitute in the formula above

$A=2,250(1+0.04*10)$

$A=2,250(1.4)$

$A=\$3,150$

step 2

Interest compounded annually

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1$

substitute in the formula above

$A=2,250(1+\frac{0.04}{1})^{1*10}$

$A=2,250(1.04)^{10}$

$A=\$3,330.55$

step 3

Find the differences between the two final amounts

$A=\$3,330.55-\$3,150=\$180.55$

5 0

2 years ago

The test statistic of z=2.08 is obtained when testing the claim that p≠0.611. a. Identify the hypothesis test as being two-tail

krek1111 [17]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

When the two-tailed were testing then:

Null and alternative hypothesis:

$H_0 : p = 0.611\\\\H_a : p \neq 0.611$

Testing the statistics:

$\to z = 2.08\\\\P-value = 0.0375\\\\\alpha = 0.01\\\\0.0375> 0.01\\\\P-value < \alpha\\\\$

therefore, it fails to reject the null hypothesis.

8 0

2 years ago

Determine whether the points (–3,–2) and (3,2) are in the solution set of the system of inequalities below. y ≤ ½x + 2 y < –2

lana [24]

Given:

The system of inequalities:

$y\leq \dfrac{1}{2}x+2$

$y$

To find:

Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.

Solution:

A point is in the solution set of the given system of inequalities if it satisfies both inequalities.

Check for the point (-3,-2).

$-2\leq \dfrac{1}{2}(-3)+2$

$-2\leq -1.5+2$

$-2\leq 0.5$

This statement is true.

$-2$

This statement is also true.

Since the point (-3,-2) satisfies both inequalities, therefore (-3,-2) is in the solution set of the given system of inequalities.

Now, check for the point (3,2).

$2$

This statement is false because $2>-9$ .

Since the point (3,2) does not satisfy the second inequality, therefore (3,2) is not in the solution set of the given system of inequalities.

7 0

2 years ago