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stellarik [79]
3 years ago
15

(2-y)/(y+7)=3/5 what is the answer

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0
Multiplying both sides by y+7, we get 2-y=(3y+21)/5 and then by multiplying both sides by 5 we get 10-5y=3y+21. After that, subtract 21 from both sides as well as add 5y to both sides to get -11=8y, so divide by 8 to get -11/8=y
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Twelve less than a number y is 8? Please help
evablogger [386]

Answer:

The answer is y = 20

Step-by-step explanation:

To find this, we need to turn it into an equation. Then we can follow the order of operations to solve.

y - 12 = 8

y = 20

7 0
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Dianne's profit from selling magazine subscriptions varies directly with the number of subscriptions sold. Dianne made $30 from
mixas84 [53]
B) I say this bcz I divided 30 by 24 and got 1.25
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3 years ago
Destiny just received two separate gifts from her great-great-grandmother.
qaws [65]

Answer:

6 bags

Step-by-step explanation:

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8 0
3 years ago
In Triangle XYZ, measure of angle X = 49° , XY = 18°, and
marissa [1.9K]

Answer:

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

Step-by-step explanation:

There are mistakes in the statement, correct form is now described:

<em>In triangle XYZ, measure of angle X = 49°, XY = 18 and YZ = 14. Find the measure of angle Y:</em>

The line segment XY is opposite to angle Z and the line segment YZ is opposite to angle X. We can determine the length of the line segment XZ by the Law of Cosine:

YZ^{2} = XZ^{2} + XY^{2} -2\cdot XY\cdot XZ \cdot \cos X (1)

If we know that X = 49^{\circ}, XY = 18 and YZ = 14, then we have the following second order polynomial:

14^{2} = XZ^{2} + 18^{2} - 2\cdot (18)\cdot XZ\cdot \cos 49^{\circ}

XZ^{2}-23.618\cdot XZ +128 = 0 (2)

By the Quadratic Formula we have the following result:

XZ \approx 15.193\,\lor\,XZ \approx 8.424

There are two possible triangles, we can determine the value of angle Y for each by the Law of Cosine again:

XZ^{2} = XY^{2} + YZ^{2} - 2\cdot XY \cdot YZ \cdot \cos Y

\cos Y = \frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ}

Y = \cos ^{-1}\left(\frac{XY^{2}+YZ^{2}-XZ^{2}}{2\cdot XY\cdot YZ} \right)

1) XZ \approx 15.193

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-15.193^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 54.987^{\circ}

2) XZ \approx 8.424

Y = \cos^{-1}\left[\frac{18^{2}+14^{2}-8.424^{2}}{2\cdot (18)\cdot (14)} \right]

Y \approx 27.008^{\circ}

There are two choices for angle Y: Y \approx 54.987^{\circ} for XZ \approx 15.193, Y \approx 27.008^{\circ} for XZ \approx 8.424.

6 0
3 years ago
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