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GaryK [48]
3 years ago
13

There are 11 women and 9 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different su

ch committees are possible? a. 120 b. 720 c. 1,060 d. 1,520 e. 1,980
Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

1980

We can choose 2 men from 9 in 36 in ways.

We can choose 2 women from 11 in 55 ways.

For any arrangement of 2 men there are 55 ways of combining them with 2 women => 55 * 36 = 1980 total ways.

If you're wondering how i got the numbers i used the combination formula:

C(n, k) = \frac{n!}{k!(n-k)!}

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Answer:

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Step-by-step explanation:

Steps

$5\left|x-2\right|+4>8$

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Show Steps

$x-2<-\frac{4}{5}\quad:\quad x<\frac{6}{5}$

Show Steps

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$\mathrm{Combine\:the\:intervals}$

$x<\frac{6}{5}\quad\mathrm{or}\quad\:x>\frac{14}{5}$

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