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GaryK [48]
3 years ago
13

There are 11 women and 9 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different su

ch committees are possible? a. 120 b. 720 c. 1,060 d. 1,520 e. 1,980
Mathematics
1 answer:
Lelechka [254]3 years ago
3 0

Answer:

1980

We can choose 2 men from 9 in 36 in ways.

We can choose 2 women from 11 in 55 ways.

For any arrangement of 2 men there are 55 ways of combining them with 2 women => 55 * 36 = 1980 total ways.

If you're wondering how i got the numbers i used the combination formula:

C(n, k) = \frac{n!}{k!(n-k)!}

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The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that \angle SQR \cong \angle XQR, then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

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