Question

There are 11 women and 9 men in a certain club. If the club is to select a committee of 2 women and 2 men, how many different such committees are possible? a. 120 b. 720 c. 1,060 d. 1,520 e. 1,980

Answer 1

Answer:

1980

We can choose 2 men from 9 in 36 in ways.

We can choose 2 women from 11 in 55 ways.

For any arrangement of 2 men there are 55 ways of combining them with 2 women => 55 * 36 = 1980 total ways.

If you're wondering how i got the numbers i used the combination formula:

C(n, k) = $\frac{n!}{k!(n-k)!}$