Eₖ = √1/2 mv²
Eₖ/v² = 1/2 m
2Eₖ/v² = m
mgh = 1/2 mv²
gh = 1/2 v²
2gh = v²
v = √2gh
= √2 × 10 N/kg × 2 m
= 6.324 ms⁻¹
m = 9.8/(6424)²
= 9.8/39.993
= 0.245 g
I am not sure if it's correct.
i transposed for m in the first equation then to find the velocity I combined the potential and kinetic energy equation. there was no mass because velocity doesn't depend on the mass
Then I used earth's gravitational field strength (g) 10 N/kg and the 2 m was the height provided in the question
you can try working and see if you get the same
Answer:
25000 J
Explanation:
Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton. meter (N. m).
Answer:
Natural processes such as waves, tides, and weather, continually change coastal landscapes. The integrity of coastal homes, businesses, and infrastructure can be threatened by hazards associated with event-driven changes, such as extreme storms and their impacts on beach and dune erosion, or longer-term, cumulative changes associated with coastal and marine processes, such as sea-level rise. Scientists working on Coastal Change Hazards conduct basic and applied research and provide relevant science-based products to assist the Nation with these coastal change hazard challenges. By building a community with a broad range of expertise, CCH facilitates the integration of diverse coastal science and the exchange of new ideas and approaches across the Coastal-Marine Hazards and Resources Program (CMHRP). Innovative collaboration is encouraged in order to identify and address the Nation’s needs and coastal change hazards problems. Through observation and modeling, CCH develops robust and accessible coastal change assessments that help improve the lives, property, and economic prosperity of the Nation’s coastal communities, habitats, and natural resources.
Explanation:
The correct answer is C) Is softer than a diamond. Hope this helps.
